Question

Which graph represents 3x2 + 3y2 – 48x + 60y + 384 = 0?

Answer 1

Answer:

3x

2

+3y

2

−48x+60y+384=0

(x−a)

2

+(y−b)

2

=r

2

isthecircleequcation

witharadiusrcentered

at(ab)

rewrite3x

2

+3y

2

−48x+60y+

384=0inthestandardof

circleequation

(x−8

2

)+(y−(−10))

2

thereforethecircleproperties

are(ab)=(8−10)r=6

answeris(8−10)r=6

Answer 2

it was helpful to you:

$3 {x}^{2} + 3 {y}^{2} - 48x + 60y + 384 = 0 \\ \\ (x - a) {}^{2} + (y - b) {}^{2} = {r}^{2} \\ is \: the \: circle \: equcation \\ with \: a \: radius \: r \: centered \\ at \: (a \: b) \\ \\ rewrite \: 3 {x}^{2} + 3 {y}^{2} - 48x + 60y + \\ 384 = 0 \: in \: the \: standard \: of \: \\ circle \: equation \\ (x - {8}^{2} ) + (y - ( - 10)) {}^{2} \\ \\ therefore \: the \: circle \: properties \\ \: are \: (a \: b) = (8 \: - 10) \: r = 6 \\ \\ answer \: is \: (8 \: - 10) \: r = 6$