Lets operate is separate parts, the whole parts and the fractions:
9 1/6 - 3 5/8
= (9 - 3) + (1/6 - 5/8)
so now we have separated the operations, but now we need to get the fractions to the same denominator using the minimum common multiple of 6 and 8, which is 48 so we convert those fractions to be divided by 48:
1/6 = (8/8)(1/6) = (8*1)/(8*6) = 8/48
5/8 = (6/6)/(5/8) = (6*5)/(6*8) = 30/48
Lets substitute those fractions and subtract:
= (9 - 3) + (1/6 - 5/8<span>)
</span>= (9 - 3) + (8/48 - 30/48<span>)
</span>= (6) + (-22/48)
We have a negative fraction and have to subtract it from the whole part, we can convert the whole part to be divided by 48 as well, so the subtraction is easy:
6 = (48/48)(6) = (48*6)/(48) = 288/48
susbstitute:
<span>= (6) + (-22/48)
</span><span>= (288/48) + (-22/48)
</span><span>= 288/48 - 22/48
</span>= 266/48
= 5 26/48
= 5 13/24
Answer:
Brandyn is 41.48m from Chris
Step-by-step explanation:
I have drawn an image depicting this question and I've attached it.
From the diagram, chris is standing at point B while Brandyn is at point D. x is the distance of brandyn to the bottom of the pole.
The height of the pole is AC.
Now, by trigonometric ratio, we can find AC. Thus;
AC/20 = tan 35
AC = 20 tan 35
AC = 14
Since,we now have AC, we can find x.
Similarly, 14/x = tan 27
x = 14 / tan 27
x = 27.48 m
Thus, total distance of brandyn from Chris = 14 + 27.48 = 41.48 m
<span>1. (f+g)(x) = f(x) +g(x)
.. = (</span>x^2-36) +(<span>x^3+2x^2-10)
.. = x^3 +3x^2 -46
2. </span>(f•g)(x) = f(x)•g(x)
.. = (x^4-9)•(x^3+9)
.. = x^7 +9x^4 -9x^3 -81
<span>3. (f-g)(x) = f(x) -g(x)
.. = (x^3-2x^2+12x-6) -(4x^2-6x+4)
.. = x^3 -6x^2 +18x -10</span>
Answer:
A
Step-by-step explanation:
A is the reasonable answer
I think it's 462.99, rounded it's 463
