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3 years ago

Please help me with this question I don’t know how to do it. PLEASE!!!!!!!!!

Mathematics

2 answers:

katen-ka-za [31]3 years ago

5 0

Answer: b. 3x - 6 = 5

Step-by-step explanation:

If you distribute the 3 into the equation this will be the correct answer

Oliga [24]3 years ago

5 0

5. 3x - 6 = 5 (Option B)

6. Make one point 0, and then make another point on (2, 1)

Second line:

y = -x + 6

Make one point on (0, 6), and then make another point on (-1, 5)

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An someone hlpe me with my problme

ahrayia [7]

Answer:

2*4ⁿ

Step-by-step explanation:

$4^{n-1}=4^n*4^{-1}\\4^{-1}= \frac{1}{4}\\8*\frac{1}{4}*4^n\\2*4^n$

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3 years ago

Wendy is logging the number of video game levels she wins per hour. She has determined the function to be f(x) = 6x + 9, where x

Savatey [412]

The answer is C because spending no time on video games gets you at least 9 for a range, and spending as much time as she wants to means the number will increase meaning "greater than"

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3 years ago

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If a vehicle travels a distance of 5t^4-10t^2+6 miles in t+2 minutes what is the vehicles speed

satela [25.4K]

speed = distance/time

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3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

A cube is 6 feet on each side. What is its volume?

zlopas [31]

36ft

Explanation: 6x6=36

3 0

2 years ago

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