<span>((P1V1/T1)=(P2V2/T2))</span>
And Example for Physical Property it’s : Gold Is Shiny
And Chemical and like a dry piece of paper burning
Answer:
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
Explanation:
Let's consider the following equation.
H₂(g) + Cl₂(g) → 2 HCl(g)
We can use the balanced equation to interpret the changes in two levels: the particulate level and the molar level.
On the particulate level, we consider discrete molecules.
On the particulate level: 1 molecule of H₂(g) reacts with 1 molecule of Cl₂(g) to form 2 molecules of HCl(g).
On the molar level, we think in terms of moles, considering 1 mole of particles = 6.02 × 10²³ particles.
On the molar level: 1 mole of H₂(g) reacts with 1 mole of Cl₂(g) to form 2 moles of HCl(g).
I think is b.an explosion hope it works
The molar enthalpy of combustion in kj/mol of magnesium is 620 kj/mol, Option D is the correct answer.
<h3>What is enthalpy of Combustion ?</h3>
The energy released when a fuel is oxidized by an oxidizing agent is called enthalpy of Combustion.
It is given that
a 1.0 g sample of magnesium is burned to form MgO. in doing so, 25.5 kj of energy are released.
Molecular weight of Magnesium = 24.35g
24.35 g makes 1 mole of Mg
1g = 1/24.35
For 0.04 moles 25.5 kJ is released
for 1 mole 25.5 *1/.04
= 620 kj/mol
Therefore the molar enthalpy of combustion in kj/mol of magnesium is 620 kj/mol.
To know more about enthalpy of combustion
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