Answer : The molar volume of the gas will be, 44.82 L
Solution :
Using ideal gas equation,
where,
n = number of moles of gas = 1 mole
P = pressure of the gas = 0.5 atm
T = temperature of the gas = 273 K
R = gas constant = 0.0821 Latm/moleK
V = volume of the gas.
Now put all the given values in the above equation, we get the molar volume of the gas.
Therefore, the molar volume of the gas will be, 44.82 L
<h3><u>Answer; </u></h3>
=10.38 moles KOH
<h3><u>Explanation</u>;</h3>
The balanced equation.
6KOH + Al2(SO4)3 --> 3K2SO4 + 2Al(OH)3
From the equation;
1 mole of aluminum sulfate requires 6 moles of potassium hydroxide.
Moles of Aluminium sulfate; 1.73 moles
Moles of KOH;
1 mol Al2(SO4)3 : 6 mol KOH = 1.73 mol Al2(SO4)3 : x mol KOH
Thus; x = (6 × 1.73)
<u> =10.38 moles KOH </u>
Answer:
Explanation:
¡Hola!
En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:
Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:
¡Saludos!
Symbiosis describes close<span> interactions between two or more different species. There are four main types of symbiotic relationships: mutualism, commensalism, parasitism and competition.</span>
When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? First you need to write a balanced chemical equation.
