A combustion reaction of an will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide
looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get
well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.
now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20
check that the H atoms balance out on both sides
Answer:
Samira's model correctly demonstrates how the properties changed with the rearrangement of the atoms. However not all atoms are accounted for. There is a missing reactant.
Explanation:
Samira's model correctly demonstrated how the atoms in two compounds reacted to form two new products. However, the elements present in the reactants side should be the elements that make up the new products in the product side. But as the diagram shows, Sameera has mistakenly added a new element to one of her products which will be wrong.
Answer:
D) How many valence electrons the atom contains.
This is the only closest one
because the number of electrons in the outermost shell is the correct answer
Answer:
C) 3.3 x 104 grams
Explanation:
1 mole of water contains 6.02 × 10^23 atoms
1.1 × 10^27 atoms will contain;
1.1 × 10^27 ÷ 6.02 × 10^23
= 0.1827 × 10^( 27 - 23)
= 0.1827 × 10^(4)
= 1.827 × 10³ moles of water.
To convert mole to mass in grams, we use the formula;
mole (n) = mass (m) ÷ molar mass (MM)
Molar mas of water (H2O) = 1(2) of H + 16 of O = 18g/mol
mole = mass/molar mass
1.827 × 10³ = mass / 18
mass = 1.827 × 10³ × 18
mass = 32.886 × 10³
mass = 3.286 × 10⁴
mass = 3.3 × 10⁴ grams
Answer:
longitudinal wave
Explanation:
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