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mr_godi [17]
3 years ago
8

Solve x + y = 100 x -y = 10 Pair of Equation

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

lets take

x+y=100 firstly.

then x=100-y equation (i)

Now,

x-y=10

Putting value of x from equation(i)

100-y-y=10

-2y=10-100

-2y=-90

therefore, y=45

Now,

putting value of y in equation(i)

we get

x=100-45

ie x=55

hence, x=55 & y=45

Nookie1986 [14]3 years ago
5 0

Answer:

The solution is (55, 45).

Step-by-step explanation:

Solve the system of linear equations

x + y = 100

x - y = 10

through elimination by addition / subtraction.

Combining these two equations temporarily eliminates y, leaving us with 2x = 110.  Then x = 55.

Substituting 55 for x in the first equation, we get:

55 + y = 100.  Subtracting 55 from both sides leaves us with y = 45.

The solution is (55, 45).

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K=mv^2/2 solve for v
matrenka [14]

Answer: v=\sqrt[]{\frac{2K}{m} }

Step-by-step explanation:

K=\frac{mv^2}{2}

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

2*K=\frac{mv^2}{2}*2

2K=mv^2

Divide by m to isolate v^2.

\frac{2K}{m}=\frac{mv^2}{m}

\frac{2K}{m} =v^2

To eliminate the square and isolate v, extract the square root.

\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}

\sqrt[]{\frac{2K}{m} }=v

let's rewrite it in a way that v is in the left side.

v=\sqrt[]{\frac{2K}{m} }

4 0
3 years ago
-2 3/7 - 1 2/3 show ur work!please
nataly862011 [7]

Answer:

-4 2/21

Step-by-step explanation:

-2 3/7 - 1 2/3

Change to improper fraction

-2 3/7 = -17/7

- 1 2/3 =-5/3

-17/7-5/3

L.C.M=21

-51-35/21

= -86/21

= -4 2/21

Hope it helps..

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1 year ago
What is the area of the rectangle?
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I believe is the right one
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sheila mixed 3 oz of blue paint wih 2 oz of yellow paint she decided to create 20 oz of he same mixture how many oz of yello pai
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Read 2 more answers
Find the area under the standard normal curve between z = −2.57 and z = 1.27. Round your answer to four decimal places, if neces
dexar [7]
P(-2.57 ≤ Z ≤ 1.27) = P(Z ≤ 1.27) - P(Z ≤ -2.57)

P(Z ≤ 1.27) = 0.8980
P(Z ≤ -2.57) = 1 - P(Z ≤ 2.57) = 1 - 0.99488 = 0.00512

P(-2.57 ≤ Z ≤ 1.27) = 0.8980 - 0.00512 = 0.89288
0.8929 (4 d.p.)
4 0
3 years ago
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