Answer:
Option C, 262 cm^3
Step-by-step explanation:
<u>Step 1: Substitute 5 for radius and 10 for height</u>
V = 1/3 * pi * r^2 * h
V = 1/3 * pi * (5)^2 * (10)
V = 1/3 * pi * 25 * 10
V = 250pi/3
V = 261.79
Answer: Option C, 262 cm^3
The answer is Beryllium atom has a larger radius by 2 times.
Nitrogen atom: 5.6 × 10⁻¹¹ = 5.6 × 10⁻¹⁻¹⁰ = 5.6 × 10⁻¹ × 10⁻¹⁰ = 0.56 × 10⁻¹⁰
Beryllium atom: 1.12 × 10⁻¹⁰
Since 1.12 is bigger than 0.56, then the radius of beryllium atom is larger of the radius of nitrogen atom. Let's see by how many times:
1.12 × 10⁻¹⁰ : 0.56 × 10⁻¹⁰ = 1.12 : 0.56 = 2
The correct statement which is true about angle 3 and 5 is, they are supplementary.
Step-by-step explanation:
- Two parallel lines are intersected by a third line so that angles 1 and 5 are congruent as they are supplementary.
- Supplementary Angles are Supplementary when the two angles are add up to 180 degrees.
- Examples of supplementary angles are 60° and 120°.
- Two lines are parallel when their slopes are equal. In order to see if the two lines are parallel, we must compare their slopes.
- A transversal is also known as a line segment, that intersects two or more other lines or also a line segments. When a transversal intersects parallel lines many angles are formed, which are known as congruent.
- If two parallel lines are intersected by a transversal, the corresponding angles are congruent.
- If two lines are intersected by a transversal, the corresponding angles are called as congruent i.e the lines are parallel.
Answer:
The angle the wire now subtends at the center of the new circle is approximately 145.7°
Step-by-step explanation:
The radius of the arc formed by the piece of wire = 15 cm
The angle subtended at the center of the circle by the arc, θ = 68°
The radius of the circle to which the piece of wire is reshaped to = 7 cm
Let 'L' represent the length of the wire
By proportionality, we have;
L = (θ/360) × 2 × π × r
L = (68/360) × 2 × π × 15 cm = π × 17/3 = (17/3)·π cm
Similarly, when the wire is reshaped to form an arc of the circle with a radius of 7 cm, we have;
L = (θ₂/360) × 2 × π × r₂
∴ θ₂ = L × 360/(2 × π × r₂)
Where;
θ₂ = The angle the wire now subtends at the center of the new circle with radius r₂ = 7 cm
π = 22/7
Which gives;
θ₂ = (17/3 cm) × (22/7) × 360/(2 × (22/7) × 7 cm) ≈ 145.7°.
