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3 years ago

7

For a normally distributed random variable x with m = 75 and s = 4, find the probability that 69 < x < 79 Use the table to

help find the answer.

1 answer:

nalin [4]3 years ago

6 0

10-14-19-12-14-18-10-15-15

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What is a third-degree polynomial function P(x) with rational coefficients so that P(x) = 0 has roots −3 and i?

Mandarinka [93]

Answer:

x²-(i-3)x- 3i

Step-by-step explanation:

What is a third-degree polynomial function P(x) with rational coefficients so that P(x) = 0 has roots −3 and i?

Given the toots of the polynomial to be -3 and i, the factors of the polynomial will be (x+3) and (x-i)

Taking the product

P(x) = (x+3)(x-i)

P(x) = x²-xi+3x-3i

P(x) = x²-(i-3)x- 3i

Hence the required polynomial is

x²-(i-3)x- 3i

3 0

3 years ago

jose brought 2 movie tickets and a box of popcorn the popcorn cost $6 and he spend a total of $24 how much did each ticket cost

Leni [432]

Each ticket costs 8 dollars

6 0

2 years ago

Read 2 more answers

There are 15 technicians and 11 chemists working in a research lab. They need to form a 5 person safety committee. In how many w

Burka [1]

<h2>There are a total 65,780 ways in which the committee can be made of 5 members.</h2>

Step-by-step explanation:

Here, the total number of technicians in the lab = 15

The total number of chemists in the lab = 11

So, the total members in the lab = 15 + 11 = 26

So, there are total 26 eligible candidates in the lab from which committee of 5 people has to be made.

Now, since there is <u>no restrictions</u> on the choice, so the committee can be formed in nay way, such that:

It may or may not have any technician.

It may or may not have may chemists.

So, the number of ways 5 member can randomly be chosen from a committee of 26 people = $^{26} C_5$

$^{26} C_5$ = $^{26} C_5 = \frac{26!}{5! \times 21!} = 65,780$

Hence, there are a total 65,780 ways in which the committee can be made of 5 members.

5 0

3 years ago

Find the missing terms of the arithmetic sequence ...,27,?,?,?,53,... Show each step of the process clearly

Alja [10]

Answer:

Step-by-step explanation:

Looking at the arithmetic sequence, the 4th term is 27 the 8th term is 53. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

Therefore, the 4th term, T4 will be

27 = a + (4 - 1) d

27 = a + 3d - - - - - - - - 1

The 8th term, t8 would be

53 = a +(8 - 1) d

53 = a + 7d - - - - - - - - -2

Subtracting equation 1 from equation 2, it becomes

- 26 = - 4d

d = - 26/- 4 = 6.5

Substituting d = 6.5 into equation 1, it becomes

53 = a + 7 × 6.5

53 = a + 45.5

a = 53 - 45.5 = 7.5

The missing terms are

7.5, 14, 20.5, 27, 33.5, 40, 46.5, 53

5 0

3 years ago

The smallest plus three times the largest of three consecutive integers is three less than five times the middle integers. Find

Murrr4er [49]

The smallest integer is 1 and middle integer is 2 and largest integer is 3

Solution:

Given that , three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.

We have to find the three consecutive integers

So, let the smallest integer be n, then the next two consecutive middle and largest integers will be n + 1, n + 2 respectively

Then, by the given statement,

Three times the largest increased by two is equal to five times the smallest increased by three times the middle integer.

Thus the smallest integer = n = 1

Middle integer = n + 1 = 1 + 1 = 2

Largest integer = n + 2 = 1 + 2 = 3

4 0

3 years ago