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Anton [14]
3 years ago
9

Ok guys this may sound bad but for an assignment I need to make a cheesey math joke ;c. Can anyone tell me one?

Mathematics
2 answers:
lakkis [162]3 years ago
6 0

Answer:

what did the triangle say to the circle? “You’re pointless”

Parallel lines have so much in common..... it’s a suene they’ll never meet.

I had an argument with a 90º angle. Turns out it was right.

Step-by-step explanation:

wolverine [178]3 years ago
3 0

Answer:

What did the triangle say to the circle? “You’re pointless.”

Step-by-step explanation:

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4²+A = can someone simplify this please
snow_lady [41]

Answer:

16+A

Step-by-step explanation:

4*4=16

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Can someone please help me with this?
mr_godi [17]
G = 2 inches


The first shape is 6 and 12. The two shapes are similar to each other, so the other shape must be 1 and 2. 6 divided by 6 is 1 so 12 divided by 6 is 2.
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What is the domain and range and function ??? Then can u explain how u did it please and thank you
enot [183]
The domain is
- 10 \leqslant x \leqslant 10
and the range is
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Because this line is a solid line rather than a dotted line, less than or equal to
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6 0
3 years ago
A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)
DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

Speed=\frac{distance}{time}

in this problem we have

distance=400\ m \\time=120\ sec

substitute in the formula

Speed=\frac{400}{120}

Speed=3.5\frac{m}{sec}

therefore

<u>the answer Part a) is</u>

the speed is equal to 3.5\frac{m}{sec}

<u>Part b) </u>Find the velocity

we know that

<u>Velocity </u>is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

magnitude=3.5\frac{m}{sec}

direction=North\ East\ (NE)

therefore

<u>the answer Part b) is</u>

the velocity is 3.5\frac{m}{sec}\ North\ East\ (NE)

Part c)

we know that

the acceleration is equal to the formula

a=\frac{V2-V1}{t2-t1}

in this problem we have

V2=0 \\V1=3.5\frac{m}{sec}

t2=15\ sec\\t1=0

substitute in the formula

a=\frac{0-3.5}{15-0}

a=-\frac{3.5}{15}\frac{m}{sec^{2}}

a=-\frac{7}{30}\frac{m}{sec^{2}}

therefore

<u>the answer Part c) is</u>

the acceleration is -\frac{7}{30}\frac{m}{sec^{2}}

This is an example of negative acceleration

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3 years ago
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