Question

If 10.0 liters of oxygen at STP are heated to 785.15 °K, what will be the new volume of gas if the pressure is also increased to 102.6 Kpa of pressure?

Answer 1

Answer: The new volume of gas is 28.5 L

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 1.00 atm (at STP)

$P_2$ = final pressure of gas = 102.6 kPa = 1.01 atm    (1 kPa= 0.0098 atm)

$V_1$ = initial volume of gas = 10.0 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $273.15K$  (STP)

$T_2$ = final temperature of gas = $785.15K$

Now put all the given values in the above equation, we get:

$\frac{1.00\times 10.0}{273.15}=\frac{1.01\times V_2}{785.15}$

$V_2=28.5L$

The new volume of gas is 28.5 L