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Dafna11 [192]
3 years ago
9

If 10.0 liters of oxygen at STP are heated to 785.15 °K, what will be the new volume of gas if the pressure is also increased to

102.6 Kpa of pressure?
Chemistry
1 answer:
Ugo [173]3 years ago
8 0

Answer: The new volume of gas is 28.5 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 1.00 atm (at STP)

P_2 = final pressure of gas = 102.6 kPa = 1.01 atm    (1 kPa= 0.0098 atm)

V_1 = initial volume of gas = 10.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 273.15K  (STP)

T_2 = final temperature of gas = 785.15K

Now put all the given values in the above equation, we get:

\frac{1.00\times 10.0}{273.15}=\frac{1.01\times V_2}{785.15}

V_2=28.5L

The new volume of gas is 28.5 L

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