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3 years ago

Which class of organic compound is commonly used in fuels?

Chemistry

2 answers:

Gelneren [198K]3 years ago

7 0

Answer:

the best answer is alcohol.

Explanation:

Advocard [28]3 years ago

3 0

Among the choices, the best answer is alcohol. However, the most common groups of organic compounds in fuels are the alkanes and alkenes. Alcohol can also be used in fuel, especially bioethanol. Bioethanol is a common additive in fuels for motor vehicles, and is made from corn or sugar.

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The Chemistry Cafe was out of bread. The cook went next door to the bakery and bought a loaf of bread which has 33 slices. Then,

maria [59]

In the question, we are told that there are;

A loaf containing 33 slices
A loaf containing 33 slices A package of cheese containing 15 slices

We also know that he is making a sandwich that has 2 pieces of both cheese and bread.

Hence;

Total number of bread and cheese = 33 + 15.

Each loaf should have two pieces of each bread and the cheeses make a total of four pieces.

Therefore he can make = 33 + 15/4 = 12 sandwiches.

4 0

2 years ago

Read 2 more answers

Do Alkali Metal Compounds form precipitates? And Why?

Alexeev081 [22]

Answer:

Alkali metal hydroxides can be used to test the identity of metals in certain salts. The colour of the precipitate will help identify the metal : Calcium hydroxide is soluble; no precipitate is formed.

6 0

2 years ago

What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?

My name is Ann [436]

Answer:

602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The yield is measured by the amount of each product produced by the reaction.

The chemical formula of fluorene is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The oxidation, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

$2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O$

To calculate the yield follow these steps:

1. Mole ratio

$2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O$

2. Convert 175mg of fluorene to number of moles

$175mg/times 1g/1,000mg=0.175g$

Number of moles = mass in grams / molar mass

$\text{number of moles}=0.175g/166.223g/mol=0.0010528mol$

3. Set a proportion for each product of the reaction

a) For CO₂

i) number of moles

$2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x$

$x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2$

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

mass = number of moles × molar mass

mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) For H₂O

i) number of moles

$0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O$

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

mass = number of moles × molar mass

mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg

4 0

3 years ago

Is the gravity a black hole strong enough to keep light from escaping True or False

puteri [66]

Answer:

The gravitational pull of a black hole is so strong that nothing, not even light, can escape once it gets too close. ... Moving at close to the speed of light, these particles ricochet off the event horizon and get hurled outward along the black hole's axis of rotation

(True)

4 0

2 years ago

Which of the following is not the same as 12.5 millimeters

jek_recluse [69]

I got 0.00125 hm . Hope I helped, and good luck(:

5 0

3 years ago