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3 years ago

Anita is making

Mathematics

1 answer:

MariettaO [177]3 years ago

3 0

Answer:

Step-by-step explanation:

I think 3

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In your notebook, draw several perpendicular lines. what kind of angles are formed? acute angles obtuse angles right angles

Ainat [17]

Right angles will be formed because in drawing
the perpendicular lines they all form right angles
to begin with. With several more draw it will
still be the same as if you are drawing one

the answer is -right angles

7 0

3 years ago

Read 2 more answers

2) f(x) = x² **<br> g(x)= 3x – 2<br> Find f(g(-4)

Usimov [2.4K]

Answer:

$f(g( - 4)) = 196$

Step-by-step explanation:

The functions are;

$f(x) = {x}^{2}$

and

$g(x) = 3x - 2$

We want to find

$f(g( - 4))$

First we find g(-4) to get:

$g( - 4) = 3 \times - 4 - 2$

$g( - 4) = - 12- 2$

$g( - 4) = - 14$

Now

$f(g( - 4)) = f( - 14)$

This implies that,

$f(g( - 4)) = {( - 14)}^{2}$

$f(g( - 4)) = {( - 14)} \times - 14$

$f(g( - 4)) = 196$

6 0

3 years ago

6) the circular base of a hemisphere of radius 2 rests on the base of a square pyramid of height 6. the hemisphere is tangent to

Rasek [7]

The length of the square base is thus $2 x 3\sqrt{2}/2 = 3\sqrt{2}$ = A

<h3>What is hemisphere?</h3>

Consequently, a hemisphere is a 3D geometric object that is made up of half of a sphere, with one side being flat and the other being a bowl-like shape. It is created by precisely cutting a spherical along its diameter, leaving behind two identical hemispheres.

EXPLANATION; Let ABCDE be the pyramid with ABCD as the square base. Let O and M be the center of square ABCD and the midpoint of side AB respectively. Lastly, let the hemisphere be tangent to the triangular face ABE at P.

Notice that triangle EOM has a right angle at O. Since the hemisphere is tangent to the triangular face ABE at P, angle EPO is also 90 degree. Hence, triangle EOM is similar to triangle EPO.

OM/2 = 6/EP

OM = 6/EP x 2

OM = $6\sqrt{6^2 - 2^2} x 2 = 3\sqrt{2}/2}$