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Lisa [10]
3 years ago
12

I need all the spaces filled in please :)

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

3x + y = -16      

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given a system of equations are

        5x+6y =-5  

       - 2x  - 5y = -11

multiply '1' and Adding two system of equtions

                 + 1      (5x   +  6y   =  -5)

                + 1      (<u> -2x    -   5y  =   -11)</u>

                   <u>       3x    +    y   = -16           </u>

<u>Final answer:-</u>

                          5x   +  6y   =  -5

                        <u> -2x    -   5y  =   -11</u>

                   <u>       3x    +    y   = -16           </u>

<u />

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<em>Samantha will earn $1,150 on the 7th day.</em>

Step-by-step explanation:

<u>Linear Modeling</u>

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Tina's (or Samantha's) earnings are $550, x, $750,... where x is an unknown amount for the second day of her new restaurant.

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FrozenT [24]
Points are collinear if they lie on the same line.

First find the equation of the line that passes through the points B and C.
B(4, -3) \\&#10;x_1=4 \\ y_1=-3 \\ \\&#10;C(-4,3) \\&#10;x_2=-4 \\ y_2=3 \\ \\&#10;m=\frac{y_2-y_1}{x_2-x_1}=\frac{3-(-3)}{-4-4}=\frac{3+3}{-8}=\frac{6}{-8}=-\frac{3}{4} \\ \\&#10;y=-\frac{3}{4}x+b \\&#10;(-4,3) \\&#10;3=-\frac{3}{4} \times (-4)+b \\&#10;3=3+b \\&#10;b=0 \\ \\&#10;y=-\frac{3}{4}x

The points lie on the line y=(-3/4)x.
Now plug the coordinates of the given points into the equation and check if they satisfy the equation.

(0,0) \\&#10;x=0 \\ y=0 \\ \Downarrow \\&#10;0 \stackrel{?}{=} -\frac{3}{4} \times 0 \\&#10;0 \stackrel{?}{=} 0 \\&#10;0=0 \\&#10;\hbox{the point lies on the line} \\ \\&#10;(1,1) \\&#10;x=1 \\ y=1 \\ \Downarrow \\&#10;1 \stackrel{?}{=} -\frac{3}{4} \times 1 \\&#10;1 \stackrel{?}{=} -\frac{3}{4} \\&#10;1 \not= -\frac{3}{4} \\&#10;\hbox{the point doesn't lie on the line}

&#10;(1,-5) \\&#10;x=1 \\ y=-5 \\ \Downarrow \\ -5 \stackrel{?}{=} -\frac{3}{4} \times 1 \\&#10;-5 \stackrel{?}{=} -\frac{3}{4} \\&#10;-5 \not= -\frac{3}{4} \\&#10;\hbox{the point doesn't lie on the line} \\ \\&#10;(6,-8) \\&#10;x=6 \\ y=-8 \\ \Downarrow \\&#10;-8 \stackrel{?}{=} -\frac{3}{4} \times 6 \\&#10;-8 \stackrel{?}{=} -\frac{9}{2} \\&#10;-8 \not= -\frac{9}{2} \\&#10;\hbox{the point doesn't lie on the line}

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