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2 years ago

Division facts for 2,5,10

Mathematics

1 answer:

docker41 [41]2 years ago

6 0

10÷5=2. 10÷2=5. They are all a factor tree

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Ed wants to buy a new video game system which costs $250. he has

BARSIC [14]

The required equation is <u>135 + 9x > 250</u>.

The number of lawns Ed must mow is assumed to be x.

The amount Ed charges for each lawn he mows is $9.

Thus, the total amount Ed earns by mowing x lawns = $9x.

The savings which Ed has is $135.

Thus, the total amount Ed will have to spend can be written as the expression, $(135 + 9x).

The cost of the video game is given to be $250.

We are asked to write an equation, that can be used to find the number of lawns Ed mow, that is x so that the amount Ed has will be more than the amount he needs to buy the video game.

This can be shown as the equation:

Total amount Ed has > Cost of the video game,

or, 135 + 9x > 250.

Thus, the required equation is <u>135 + 9x > 250</u>.

Learn more about writing equations at

brainly.com/question/25235995

#SPJ1

3 0

11 months ago

Can an expert help with this

SVEN [57.7K]

The formula of an area of a circle:

$A_O=\pi r^2$

We have

r = 1.8 m

π ≈ 3.14

Substitute:

$A_O=\pi\cdot1.8^2=3.24\pi\ m^2\approx3.24\cdot3.14=10.1736\ m^2\approx10.17\ m^2$

7 0

2 years ago

The price of a mat is x USD from the start. Write an expression for the price:

Serga [27]

Answer:

Hello good evening friend

5 0

1 year ago

If wx = XZ, then WX = YZ

EleoNora [17]

False, because there is not enough information to prove that it is true

hope this helps

5 0

2 years ago

Read 2 more answers

Evaluate the integral by changing to polar coordinatesye^x dA, where R is in the first quadrant enclosed by the circle x^2+y^2=2

34kurt

$\displaystyle\iint_Rye^x\,\mathrm dA=\int_{\theta=0}^{\theta=\pi/2}\int_{r=0}^{r=5}r^2\sin\theta e^{r\cos\theta}\,\mathrm dr\,\mathrm d\theta$

which follows from the usual change of coordinates via

$\begin{cases}\mathbf x(r,\theta)=r\cos\theta\\\mathbf y(r,\theta)=r\sin\theta\end{cases}$

and Jacobian determinant

$|\det J|=\left|\begin{vmatrix}\mathbf x_r&\mathbf x_\theta\\\mathbf y_r&\mathbf y_\theta\end{vmatrix}\right|=|r|$

Swap the order, so that the integral is

$\displaystyle\int_{r=0}^{r=5}\int_{\theta=0}^{\theta=\pi/2}r^2\sin\theta e^{r\cos\theta}\,\mathrm d\theta\,\mathrm dr$

and now let $\sigma=r\cos\theta$ , so that $\mathrm d\sigma=-r\sin\theta$ . Now, you have

$\displaystyle\int_{r=0}^{r=5}\int_{\sigma=0}^{\sigma=r}re^\sigma\,\mathrm d\sigma\,\mathrm dr=\int_{r=0}^{r=5}r(e^r-1)\,\mathrm dr=4e^5-\dfrac{23}2$

7 0

2 years ago