The surface area of the pyramid will be given as follows:
Area of triangles:
A=1/2×base×height
A=1/2×12×18
A=108 m²
Area of 6 triangles is given by:
A=108×6=648 m²
Area of the hexagon:
A=6×1/2×12×6√3
A=374.123m²
Total surface area:
SA=648+374.123
SA=1022.123 m²~1022 m²
Answer: C] 1022 m²
Answer:
hehehe
Step-by-step explanation:
☠️☠️☠️️
A right triangle can be considered as a special type
because the relationship of its sides can be described using the hypotenuse
formula:
c^2 = a^2 + b^2
or
c^2 = x^2 + y^2
where,
c is the hypotenuse of the triangle and is the side
opposite to the 90° angle
while a and b are the sides adjacent to the 90° angle
In the problem statement, we are given that one of the
side has a measure of 2 = x, while the hypotenuse is 5 = c, therefore calculating
for y:
y^2 = c^2 – x^2
y^2 = 5^2 – 2^2
y^2 = 21
y = 4.58
The natural number is the number before the decimal.
Therefore the answer is:
y = 4
Total-107
Male teacher-n
Female teacher-n+23
N+n+23=107
2n+23=107
2n= 84
N=42
Male teacher-42
Female teacher-42+23=65
65/107 teacher are female
Answer:
y=x-1
Step-by-step explanation:
