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3 years ago

H(x)=2x3 – 3 Find h(2)

1 answer:

8 0

When it tells you to find h(2), that means you plug in 2 for x.
If 2x^3 (to the third power)
2(2)^3-3

1. PEMDAS, exponents first
2^3=8

2. multiply
8x2=16

3. subtract
16-3=13

Hope this helps!

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Write an equation for the graph, where y depends on x.

Over [174]

Answer:

y = -3x + 6

Step-by-step explanation:

Equation of straight line is given by,

y = mx + b

m = slope of the line

b = y-intercept

From the graph attached,

m = $\frac{\text{Rise}}{\text{Run}}$

= $\frac{-6}{2}$

= -3

y intercept 'b' = 6

Therefore, equation of the line will be,

y = -3x + 6

5 0

3 years ago

What is the measure of

Irina18 [472]

The measure of angle A in the isosceles triangle ABC is equal to 120 degrees.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

In the triangle ABC, AB = BC = 8. Triangle ABC is an isosceles triangle and ∠B = ∠C = 30° (base angles are equal).

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

∠A + 30 + 30 = 180

∠A = 120°

The measure of angle A in the isosceles triangle ABC is equal to 120 degrees.

Find out more on equation at: brainly.com/question/2972832

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4 0

2 years ago

When planning road development, the road commission

xxTIMURxx [149]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can you figure this out? And then show your work plz?

Salsk061 [2.6K]

Step-by-step explanation:

You can use PEMDAS to solve this problem from left to right.

First, do 15 ÷ 3 to get 5.

Next, do 2 x 10 to get 20.

Lastly, add 5 and 20 to get 25.

<u>15 ÷ 3</u> + 2 x 10

5 + <u>2 x 10</u>

3 0

3 years ago

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5. Solve using any method.<br> y = -x + 8<br> y=x+4

vlada-n [284]

Answer:

Step-by-step explanation:

$\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

$\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

7 0

3 years ago