All categories

3 years ago

Nature of roots the determining 2x²-13x+15=0

Mathematics

1 answer:

nata0808 [166]3 years ago

3 0

Answer:

Step-by-step explanation:

discriminant = (-13)² - 4·2·15 = 49

discriminant > 0 so there are two real roots

You might be interested in

Six out of ten people reported they like coffee. What percent of people

Tatiana [17]

Since 6 out of 10 people reported they liked coffee then 60% of people reported they liked coffee

5 0

3 years ago

Read 2 more answers

Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)

vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

Two angles are said to be supplementary when they add up to 180°.

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

Two angles are said to be complementary when they add up to 90°.

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0

3 years ago

8) through: (-3, -2), perp. to y = x – 1 A) y=-5x – 1 B) y=-4x – 5 C) y=-x – 5 D) y=-5x – 4

nexus9112 [7]

Answer:

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

Solution:

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1$

We know that, product of slopes of perpendicular lines is -1.

So, 1 $\times$ slope of perpendicular line = -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)$

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0

3 years ago

7p+5q+4p-2q what is the result of combining the like terms

Ahat [919]

Answer:

11p+7q

Step-by-step explanation:

3 0

3 years ago

A swimming pool is 20 feet wide and 40 feet long. If it is surrounded by a walkway of square tiles, each is 1 foot by 1 foot, ho

Lena [83]

Answer:

124 tiles

Step-by-step explanation:

2(20+40)

2(60)

120+4=124

5 0

2 years ago