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vampirchik [111]
3 years ago
14

Find the slope of the line that contains the point (-2,-5) and (6,-1) show your work

Mathematics
2 answers:
mixas84 [53]3 years ago
6 0

Answer:

\frac{1}{2}

Step-by-step explanation:

(-2,-5) (6,-1)

\frac{y2 - y1}{x2 - x1}

\frac{-1 + 5}{6 +2}

\frac{4}{8} = \frac{1}{2}

Degger [83]3 years ago
5 0

Answer:

m = 1/2

Step-by-step explanation:

You need to use the m = Y2 - Y1 / X2 - X1. m is the slope variable.

y2 = -1

y1 = -5

x2= 6

x1 = -2

Then you plug it in the formula

m = -1-(-5)/6-(-2)

In the equation, there are two double negative which will become positive.

-1+5/6+2 = 4/8

Then you know 4 is one half of 8 so you can reduce the fraction to 1/2

Hope this helps!!

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8 0
3 years ago
What is the volume??????
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Answer:

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Step-by-step explanation:

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I would appreciate Brainliest but no worries.

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\it \mathcal{V} =\dfrac{\mathcal{A}_b\cdot h}{3} \Rightarrow h = \dfrac{3\mathcal{V}}{\mathcal{A}_b}= \dfrac{3\cdot3072}{\mathcal{A}_b}\ \ \ \ \ (*)&#10;\\\;\\ \\\;\\&#10;\mathcal{A}_b = \dfrac{\ell^2\sqrt3}{4} = \dfrac{16^2\sqrt3}{4} =\dfrac{16\cdot16\sqrt3}{4} =4\cdot16\sqrt3=64\sqrt3\ \ \ \ (**)&#10;\\\;\\ \\\;\\&#10;(*),\ (**) \Rightarrow h=\dfrac{3\cdot3072}{64\sqrt3} = \dfrac{3\cdot48}{\sqrt3} = \dfrac{\sqrt3\cdot\sqrt3\cdot48}{\sqrt3} = 48\sqrt3\  inches


4 0
3 years ago
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