Answer:

Find the midsegment of the triangle which is parallel to CA.

Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

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Answer:Multiply the denominator on the bottom of the fraction by the whole number you are dividing by.
To divide a fraction by a whole number, multiply the bottom of the fraction by this whole number.
The denominator on the bottom of the fraction is 7.
We will multiply 7 by 2.
7 × 2 = 14 and so, 6 / 7 ÷ 2 = 6 / 14 .
Step-by-step explanation:
Answer:
x = 97.6
Step-by-step explanation:
cos = adjacent over hypotenuse

* multiply each side by x *

* divide each side by cos ( 55 ) *

we're left with x = 97.63302055
Our last step is to round to the nearest tenth of a foot
We get that x = 97.6
The <u>correct answer</u> is:
16/45.
Explanation:
We want the probability that a student's eye color is blue if they made an A in physics. This means we look at the column for students with an A.
There are 32 students with blue eyes in the A column.
This is out of 32+58=90 students that made an A.
This makes the probability 32/90, which simplifies to 16/45.