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daser333 [38]
3 years ago
11

In a popular online role playing game, players can create detailed designs for their character's "costumes," or appearance. Huds

on sets up a website where players can buy and sell these costumes online. Information about the number of people who visited the website and the number of costumes purchased in a single day is listed below.
224 visitors purchased no costume.
103 visitors purchased exactly one costume.
32 visitors purchased more than one costume.

Based on these results, express the probability that the next person will purchase no costume as a percent to the nearest whole number.
Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

62%

Step-by-step explanation:

Given the information :

224 visitors purchased no costume.

103 visitors purchased exactly one costume.

32 visitors purchased more than one costume.

Based on these results, express the probability that the next person will purchase no costume as a percent to the nearest whole number.

Probability that next person will purchase no custome:

Probability = no of successes / total number of trials

Total number of trials :

(purchase no custome + purchase exactly one + purchase more than one)

= (224 + 103 + 32) = 359

Hence, Probability that next person will purchase no custome:

= 224 / 359

As a percentage :

(224 / 359) * 100%

= 0.6239554 * 100%

= 62.39 %

= 62% ( nearest whole percent)

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3 years ago
1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno
Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, H_0 : \mu = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, H_1 : \mu\neq 100  {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

               T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ N(0,1)

where, Xbar = sample mean score = 113

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             n = sample of students = 144

So, test statistics = \frac{113-100}{\frac{15}{\sqrt{144} } }

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Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

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Answer:d

Step-by-step explanation:

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Answer:

It depends.

Step-by-step explanation:

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37 \div 6 = 6 \frac{1}{6}

But if we can't break them, then each person will get six figures with one remaining ungiven.

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Answer:

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Hope this helps, good luck!

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