Answer:
Explanation:
the cross-sectional area of the gold nucleus / the cross-sectional area of the atom = 2.6 x 10⁻⁷
value of radius of gold atom = 1.4 x 10⁻¹¹
cross sectional area = π x (1.4 x 10⁻¹¹ )²
= 6.15 x 10⁻²² Putting this value in the ratio above
the cross-sectional area of the gold nucleus / 6.15 x 10⁻²² = 2.6 x 10⁻⁷
the cross-sectional area of the gold nucleus = 16 x 10⁻²⁹
radius of nucleus R
π R² = 16 x 10⁻²⁹
R² = 5.1 X 10⁻²⁹
R = 7.14 x 10⁻¹⁵ .
Potential energy=PE
PE=mgh
m=mass in kilograms.
g=9.8 m/s
h=height in meters
Data:
mass=500 Kg
h=110 m
PE=(500 Kg)(9.8 m/s²)(110 m)=539000 joules
answer: The potential energy of this train would be 539000 J.