If
is a random variable representing your winnings from playing the game, then it has support

There are 52 cards in the deck. Only the 1s, 2s, and 3s fulfill the first condition, so there are 12 ways in which you can win $43. So
has PMF

You can expect to win
![E[W]=\displaystyle\sum_ww\,P(W=w)=\frac{43\cdot3}{13}-\frac{11\cdot10}{13}=\boxed{\frac{19}{13}}](https://tex.z-dn.net/?f=E%5BW%5D%3D%5Cdisplaystyle%5Csum_ww%5C%2CP%28W%3Dw%29%3D%5Cfrac%7B43%5Ccdot3%7D%7B13%7D-%5Cfrac%7B11%5Ccdot10%7D%7B13%7D%3D%5Cboxed%7B%5Cfrac%7B19%7D%7B13%7D%7D)
or about $1.46 per game.
Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Depends on the original point
Answer:
1 2/7
Step-by-step explanation:
4.5:3 1/2
45/10 ÷ 7/2
45/10 x 2/7
90/70=9/7
=1 2/7
You would write 5/3 for it to be an improper fraction