In ΔEFG, e = 210 cm, f = 520 cm and g=510 cm. Find the measure of ∠G to the nearest degree. PLEASE VERY URGENT.
2 answers:
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F⁻¹(x) stands for the invers of function f(x). The inverse of f(x) is equal to x. We need to solve for x.
solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
x =
f⁻¹(x) =
Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) =
f⁻¹(4) =
f⁻¹(4) =
f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1
solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
x =
f⁻¹(x) =
Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) =
f⁻¹(4) =
f⁻¹(4) =
f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1
She sold 42 oranges with profit 20%
Step-by-step explanation:
The woman sells 90 oranges by RS.160
This price with discount of 20%
We need to find how many oranges she sell by Rs.112 with profit of 20%
- Selling price = cost price - discount ⇒ discount case
- Selling price = cost price + profit ⇒ profit case
Assume that cost price of an orange is x
∵ She sells 90 oranges with Rs.160
- Find the selling price of 1 orange by dividing 160 by 90
∴ The selling price of an orange =
∵ She sold them with discount 20%
∵ The cost price of an orange is x
- Find the 20% of x
∵ Discount = 20% × x = × x = 0.2x
- To find the selling price subtract 0.2x from x
∴ The selling price = x - 0.2x
∴ The selling price of an orange = 0.8x
- Equate 0.8x by to find x
∵ 0.8x =
- Divide both sides by 0.8
∴ x =
Assume that the number of oranges is y
∵ She sell y oranges for Rs.112 with profit 20%
∵ The cost price of an orange is
- Find 20% of
∵ Profit = 20% × =
- Add to cost price to find the selling price
∴ The selling price of an orange = +
∴ The selling price of an orange =
- To find y divide 112 by selling price of an orange
∵ y = 112 ÷
∴ y = 42
She sold 42 oranges with profit 20%
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