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spin [16.1K]
3 years ago
15

In ΔEFG, e = 210 cm, f = 520 cm and g=510 cm. Find the measure of ∠G to the nearest degree. PLEASE VERY URGENT.

Mathematics
2 answers:
Olegator [25]3 years ago
5 0

Answer:

76°

Step-by-step explanation:

Alexeev081 [22]3 years ago
5 0

Answer:

76

Step-by-step explanation:

Delta Math

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One number is 7 more than another. The difference between their squares is 161. What are the numbers?
sergeinik [125]
X is 7 more than y
x>y then
difference betwen squares is 161 so


x=7+y
and
x²-y²=161

so
x=7+y
sub that for x in other equation

(7+y)²-y²=161
y²+14y+49-y²=161
14y+49=161
minus 49 both sides
14y=112
divide both sides by 14
y=8

sub back

x=7+y
x=7+8
x=15

the numbers are 15 and 8
3 0
3 years ago
Read 2 more answers
Please help me with this one
Whitepunk [10]

Answer:

Which school do you attend please and which grade are you in please

6 0
3 years ago
A box measures 3 1/2 ft by 1 1/3 ft by 2/14 ft what is the volume
asambeis [7]

Answer: 2/3^3

Step-by-step explanation:

To find the volume of a box, you use the formula, Lenth*Width*Height=Volume

The Lenth is 3 1/2. The width is 1 1/3 and the height is 2/14

Plug the values in formula

3 1/2*1 1/3*2/14

Covert the mixed numbers into imporper fractions so it is easier to solve

3 1/2=7/2

1 1/3=4/3

7/2*4/3*2/14

Reduce 2/14

2/14=1/7

7/2*4/3*1/7=7*4*1/(2*3*7)=28/42

Reduce 28/42=14/21=2/3

2/3 ft^3

5 0
3 years ago
a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
Help! no links please!
Simora [160]

Answer: D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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