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Maslowich
3 years ago
15

1. Let f(1) = 722 – 5x + 3 and g(1) = 22² + 45 – 6.7x2-5x+3

Mathematics
1 answer:
Basile [38]3 years ago
5 0

Answer:

The correct answer is B

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What is the value of x and y?
kramer
Angles in a triangle add up to 180 degrees.

All angles in an equilateral triangle have equal values

Both angle x and y equal 60 degrees.
4 0
3 years ago
on a piece of paper, graph y<-3/4x+2. Then determine which answer choice matches the graph you drew.
exis [7]

Answer:

  D.  Graph D

Step-by-step explanation:

The  "y <" tells you two things: (1) shading will be below the line, where y-values are less than those on the line, and (2) the line will be dashed, because the "equal to" case is not included.

Only one graph has a dashed line with shading below: Graph D.

7 0
3 years ago
Which expression can be used to find the surface area of the following rectangular prism ?
Igoryamba

Answer:

i think.c) is correct answrr

6 0
3 years ago
Which rational exponent represents a square root?<br> A. 1 / 2<br> B. 3/2<br> C. 1/3<br> D. 1/4
Fofino [41]

Answer:

1/2 rational exponent represents a square root.

Therefore, option A is correct.

Step-by-step explanation:

As we know that raising to the one-half power i.e. \frac{1}{2} is the same

as taking the square root.

  • so x^{\frac{1}{2}} is the same as the square root of x.

For example, taking the square root of 4 will determine:

4^{\frac{1}{2}}

\mathrm{Factor\:the\:number:\:}\:4=2^2

4^{\frac{1}{2}}=\left(2^2\right)^{\frac{1}{2}}

\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0

\left(2^2\right)^{\frac{1}{2}}=2^{2\cdot \frac{1}{2}}

so the expression becomes

4^{\frac{1}{2}}=2^{2\cdot \:\frac{1}{2}}

    =2^1

    =2         ∵ \mathrm{Apply\:exponent\:rule}:\quad \:a^1=a

so, 1/2 rational exponent represents a square root.

Therefore, option A is correct.

5 0
2 years ago
Read 2 more answers
Solve for m. x^3×y^2(x^2×y^3×z^m/z^-5)= x^5y^5z
natta225 [31]

Answer:

M = -4

Hope I helped :D

Step-by-step explanation:

3 0
3 years ago
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