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2 years ago

Solve each compound inequality. Graph your solutions. 5 + m > 4 or 7m< -35

Mathematics

1 answer:

Yuliya22 [10]2 years ago

5 0

Answer:

Solving the inequality $5 + m > 4\: or\: 7m< -35$ we get $\mathbf{m>-1\:or\: \:m$

The graph of the inequality is shown in figure attached.

Step-by-step explanation:

We need to Solve each compound inequality $5 + m > 4\: or\: 7m< -35$

Solving the inequalities

For solving compound inequalities we solve both inequalities simultaneously and find the value of m.

For solving 5+m > 4, we subtract 5 from both sides.

While solving 7m < -35, we divide both sides by 7 to get value of m

Applying these functions we get:

$5 + m > 4\: or\: 7m< -35\\m>4-5\:or\:m-1\:or\:m$

So, solving the inequality $5 + m > 4\: or\: 7m< -35$ we get $\mathbf{m>-1\:or\: \:m$

The graph of the inequality is shown in figure attached.

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What is the simplified form of 12x/900x²y4z6?

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Answer:

$360xy^2|xz^3|$

Step-by-step explanation:

Given expression:

$12x \sqrt{900x^2y^4z^6}$

$\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:$

$\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

Replace 900 with 30² :

$\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

$\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:$

$\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}$

$\implies 360x|x|\sqrt{y^4}\sqrt{z^6}$

(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).

$\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:$

$\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}$

Simplify:

$\implies 360xy^2|xz^3|$

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).

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