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dybincka [34]
2 years ago
11

Solve each compound inequality. Graph your solutions. 5 + m > 4 or 7m< -35

Mathematics
1 answer:
Yuliya22 [10]2 years ago
5 0

Answer:

Solving the inequality 5 + m > 4\: or\: 7m< -35 we get \mathbf{m>-1\:or\: \:m

The graph of the inequality is shown in figure attached.

Step-by-step explanation:

We need to Solve each compound inequality 5 + m > 4\: or\: 7m< -35

Solving the inequalities

For solving compound inequalities we solve both inequalities simultaneously and find the value of m.

For solving 5+m > 4, we subtract 5 from both sides.

While solving 7m < -35, we divide both sides by 7 to get value of m

Applying these functions we get:

5 + m > 4\: or\: 7m< -35\\m>4-5\:or\:m-1\:or\:m

So, solving the inequality 5 + m > 4\: or\: 7m< -35 we get \mathbf{m>-1\:or\: \:m

The graph of the inequality is shown in figure attached.

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Mkey [24]
Probability of an Ace= 4/52
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Probability of an Ace or a King = P(Ace) + P(King)
=4/52 +4/52
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8 0
3 years ago
Solve for x<br>(21x-9)<br>27<br>x=​
garik1379 [7]

Answer:

3(7x-3)

Step-by-step explanation: I factor it.

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2 years ago
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Which ordered pair in the form (a, b) is a solution of this equation?
Evgen [1.6K]

3a - 4b = 21


check (-2 , -3)


3(-2) -4(-3) =21


-6 +12  = 21


6 does not = 21  so NO


check (0 , 7)


3(0) -4(7) =21


0-28=21


-28 does not equal 21  so NO


check (-3 , -2)


3(-3) -4(-2) =21


-9 +8  = 21


1 does not = 21  so NO


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5 0
3 years ago
A(n - 3) +8= bn for n please help me
Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}

On right (b-A) paranthiss cancelled and we get n on right side.

\frac{(-3A+8)}{(b-A)} =n   Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

7 0
3 years ago
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