Answer:
The right word to fill the blank space is GREATER THAN.
Explanation:
In nature, heat in form of temperature is usually transfer from the region of higher temperature to the region of lower temperature. Thus, for heat to be transfer from one substance to another one, the temperature will flow from the body with the higher temperature to that which has a lower temperature, the substance that is giving out the heat must have a higher temperature.
Molar solubility is number of moles of the solute that can be dissolved per liter of solution before the solution becomes saturated.
The molar solubility of lead(ii) chloride with ksp value of 2.4 × 10e4 can be solve as:
Ksp = s2 = 2.4 × 10e4
s2 = 2.4 × 10e4
s = √(2.4 × 10e4)
s = 154.9 mol/L
Answer:
hydrogen ions (H⁺) and chloride ions (Cl⁻)
Explanation:
Hydrochloric acid (HCl) is a strong acid. That means that the compound dissociates completely into ions when is dissolved in water, as follows:
HCl → H⁺ + Cl⁻
The equilibrium is completely shifted to the right side (products). Thus, it is considered that the concentration of the non-dissociated compound (HCl) is negligible, and the major specials present in the solution are the hydrogen ions (H⁺) and chloride ions (Cl⁻).
Answer:
mass = 0.907865 grams
Explanation:
From the periodic table:
molar mass of Li = 6.941 grams
molar mass of F = 18.998 grams
Therefore:
molar mass of LiF = 6.941 + 18.998 = 25.939 grams/mole
number of moles can be calculated as follows:
number of moles = mass / molar mass
We have:
number of moles = 0.035 moles
molar mass = 25.939 grams/mole
Substitute in the equation to get the mass as follows:
0.035 = mass / 25.939
mass = 0.035 * 25.939 = 0.907865 grams
Hope this helps :)
Answer:
Empirical formula of compound is C₄H₈O
Explanation:
Given data:
Mass of compound = 5.60 g
Mass of CO₂ = 13.7 g
Mass of H₂O = 5.60 g
Empirical formula of compound = ?
Solution:
Percentage of C:
13.7 g/5.60 g × 12/44× 100
2.45×0.273× 100 = 66.9%
Percentage of H:
5.60 g/ 5.60 g × 2.016/18 × 100
11.2%
Percentage of O:
(66.9% + 11.2%) - 100 = 21.9%
Grams atom of C , H, O
66.9/12 = 5.6
11.2 / 1.008 = 11.11
21.9 / 16 = 1.4
Atomic ratio:
C : H : O
5.6/1.4 : 11.11/1.4 : 1.4/1.4
4 : 8 : 1
Empirical formula:
C₄H₈O
