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kondor19780726 [428]
3 years ago
15

Matt and Ming are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges. Ma

tt sold 3 small boxes of oranges and 14 large boxes of oranges for a total of $203. Ming sold 11 small boxes of oranges and 11 large boxes of oranges for a total of $220. Find the cost of each of one small box of oranges and one large box of oranges. show work
Mathematics
2 answers:
VikaD [51]3 years ago
5 0

Answer: $20 for each box

Step-by-step explanation:

So all you do is get the total of the cost and then divide it by how many he sold. So if im correct its 20.

dybincka [34]3 years ago
4 0

Answer:

Hope this helps ;)

Step-by-step explanation:

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Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Luda [366]

Answer:

It is 300.88.

Step-by-step explanation: In order for the perimeter of the base to be 18.2, the length and width would have to be 9.1, knowing this, you can plug it into the formula for a pyramid like usual with the height provided.

5 0
2 years ago
Sutopa has 3/4 of the money Maneet has. Maneet has $18 less than Kim. Together, they have $286.40. How much money does each of t
anastassius [24]

Solving a system of equations we can see:

  • Sutopa has $73.20
  • Maneet has $97.60
  • Kim has $115.60

<h3>How much money each of them has?</h3>

First, let's define the variables:

  • S =  money that Sutopa has.
  • M = money that Maneet has.
  • K = money that Kim has.

We can write the system of equations:

S = (3/4)*M

M = K - $18

S + M + K = $286.40

First, we can rewrite the second equation to get:

K = M + $18

Now we can replace the first and second equations into the third one:

(3/4)*M + M + (M + $18) = $286.40

Now we can solve this for M:

M*(1 + 1 + 3/4) = $286.40 - $18

M = $268.40*(4/11) = $97.60

Now we can find the other two values:

K = M + $18 =  $97.60 + $18 = $115.60

S =  (3/4)*M =  (3/4)*$97.60 = $73.20

If you want to learn more about systems of equations:

brainly.com/question/13729904

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6 0
2 years ago
Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 12 ca
Ksju [112]

Answer:

a) 45 possible outcomes

b) 55 possible outcomes

Step-by-step explanation:

Given:

- Total cavities = 12

- Selection = 3 parts

- Non-conforming cavities = 2

Find:

a) How many samples contain exactly 1 nonconforming part?

b) How many samples contain at least 1 nonconforming part?

Solution:

- The question asks for the use of combinations to express the outcomes for each scenario.

- For first part, we want the inspector to pick exactly one non-conforming part among 3 selected. So let us say that he has already chosen that one non conforming cavity. Now he has to make 2 more selections out of total conforming cavities = 12 - 2 = 10 conforming cavities. Hence, the total possible outcome is to chose 2 randomly from 10 conforming cavities.

                              ( Exactly 1 ) 10C2 = 45 possible outcomes

- The second part entails that at-least 1 non-conforming cavity is selected. To choose exactly 1 non conforming we calculated above. In the similar way calculate for selecting exactly 2 non-conforming cavities. The total possible outcome would be to choose from 10 conforming and we choose 1 from it:

                              ( Exactly 2 ) 10C1 = 10 possible outcomes

- Hence, for at-least 1 non conforming cavity being selected we same the above two cases calculated:

                             (At-least 1 ) =  ( Exactly 1 ) +  ( Exactly 2 )

                             (At-least 1 ) =  45 + 10 = 55 possible outcomes

4 0
3 years ago
-5.42 , 5 5/6 , 5.34 , -5 4/5<br><br> Least to greatest please
polet [3.4K]

-5 4/5, -5.42, 5.34, 5 5/6

3 0
2 years ago
By how much does 5 exceed -4?<br>(a) 1<br>(b)-1<br>(c) 9<br>(d) -9​
Elden [556K]

Answer:

C

Step-by-step explanation:

-4+9=5

6 0
3 years ago
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