Question

A Chef prepares and evenly divides s ounces of beef stock into 3 smaller pans. The chef uses 8 ounces of beef stock form one of he smaller pans, and 34 ounces of beef stock remain in that smaller pan. Write an equation that correctly represents the number of ounces of beef stock, s, that the chef initially prepares.

Answer 1

Answer:

Thus, the equation hat correctly represents the number of ounces of beef stock, $s$, that the chef initially prepares.

⇒ $\frac{s}{3}-8=34$

The total number of ounces of beef stock = 126

Step-by-step explanation:

Given:

Total ounces of beef stock = $s$

The chef divided the beef stock  evenly into 3 smaller pans.

The chef then uses 8 ounces from one of the smaller pans.

Ounces of beef stock left in the smaller pan = 34

Solution:

Total ounces of beef stock = $s$

Ounces of beef stock in each smaller pan = $\frac{s}{3}$

Ounces of beef stock used by the chef from the smaller pan = 8.

The ounces of beef stock left in the smaller pan will be given as:

⇒ $\frac{s}{3}-8$

Ounces of beef stock remaining in smaller pan = 34

Thus, the equation hat correctly represents the number of ounces of beef stock, $s$, that the chef initially prepares.

⇒ $\frac{s}{3}-8=34$

Solving for $s$.

Adding 8 both sides.

⇒ $\frac{s}{3}-8+8=34+8$

⇒ $\frac{s}{3}=42$

Multiplying both sides by 3.

⇒ $3\times \frac{s}{3}=42(3)$

∴ $s=126$

Thus, total number of ounces of beef stock = 126