Solve for w and simplify this fraction 3/2w=-20

Mathematics

1 answer:

AleksAgata [21]2 years ago

6 0

Answer:

If I'm correct, the answer should be negative 40/3.

Step-by-step explanation:

Because you first combine multiplied terms into a single fraction, then you multiply all terms by the same value to eliminate fraction denominators. Now you simplify it, by canceling multiplied terms that are in the denominator and then you multiply the numbers. Now you will divide both sides of the equation by the same term. Finally, you will simplify the equation.

(Hope this helps) I had to get a little help myself on this problem)

You might be interested in

9a - ab + 5b if a = 2 and b = 7

Anit [1.1K]

9a-ab+5b
9(2)-(2)(7)+5(7)
18-14+35
39

8 0

2 years ago

Find all roots: x^3-7x^2-12x = 0

Pepsi [2]

Answer:

The roots are 0, 3 and 4.

Step-by-step explanation:

x^3-7x^2-12x = 0 Take out x:

x(x^2 - 7x - 12) = 0 Factor the expression in the brackets:

x(x - 3)(x - 4) = 0

x = 0 or x - 3 = 0 or x - 4 = 0, so

The roots are 0, 3 and 4.

5 0

2 years ago

Can you help me solve this?

Wittaler [7]

Answer:

y=-1/2x+4 Is your answer

Step-by-step explanation:

y=mx+b

3=2x+4

-1=2x

x=-1/2

You already know y is 4 so y=-1/2x+4

4 0

3 years ago

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$