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e-lub [12.9K]
3 years ago
8

For Quon's first 6 quizzes he had a mean score of 33 points. After his 7th quiz his mean score was 32 points. After the 8th quiz

the mean was 34. What was the difference in scores between his 7th and 8th quizzes
Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

Difference in scores between his 7th and 8th quizzes = 22

Step-by-step explanation:

Given: Mean score for first 6 quizzes is 33 points. After his 7th quiz his mean score was 32 points. After the 8th quiz the mean was 34.

To find: difference in scores between his 7th and 8th quizzes

Solution:

Mean scores = Total points scored in quizzes ÷ Number of quizzes

So,

Total points scored in quizzes = Mean scores × Number of quizzes

As mean score for first 6 quizzes is 33 points,

Total points scored in 6 quizzes = 6 × 33 = 198

As mean score for first 7 quizzes is 32 points,

Total points scored in 7 quizzes = 7 × 32 = 224

So,

7th score = Total points scored in 7 quizzes - Total points scored in 6 quizzes

               = 224 - 198

               = 26

As mean score for first 8 quizzes is 34 points,

Total points scored in 8 quizzes = 8 × 34 = 272

So,

8th score = Total points scored in 8 quizzes - Total points scored in 7 quizzes

               = 272 - 224

               = 48

Therefore,

Difference in scores between his 7th and 8th quizzes = 48 - 26

                                                                                          = 22

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3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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Answer:

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

Step-by-step explanation:

<u><em>Explanation</em></u>

<em>Given       </em>\frac{14}{8} + \frac{15}{12}<em></em>

<em></em>

<em>L.C.M     8 , 12   is  24</em>

<em>          </em>

<em>        </em>\frac{14}{8} + \frac{15}{12} = \frac{14 X 3 + 15 X 2}{24}<em></em>

<em>                   = </em>\frac{42 +30}{24} = \frac{72}{24} = 3<em></em>

<u><em>Final answer</em></u><em>:-</em>

The value of <em> </em>\frac{14}{8} + \frac{15}{12}  = 3

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Rewrite as:

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Express 60 as a product

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See attachment for the drawing that represents the bundle

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The 6 in 62 can be interpreted in the following ways

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Read more about base-ten units at:

brainly.com/question/12386995

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