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TiliK225 [7]
3 years ago
9

A rectangular floor of area 360 m2 is going to be tiled. Each tile is rectangular, and has an area of 240 cm2. An exact number o

f tiles can be put into the space. How many tiles will be needed??​
Mathematics
2 answers:
larisa [96]3 years ago
6 0

Answer:

\displaystyle\rm  15000

Step-by-step explanation:

we given the area of rectangular floor and tile we want to find the number of tiles needed to tile the floor

notice that the area of the rectangular floor is in meter and the tile in cm so we need to convert cm to meter in order to figure out the number of tiles needed to tile the floor

therefore,

\rm 1m \implies 100 c m\\   \rm{1m}^{2}  \implies10000 {cm}^{2}

remember that,

\displaystyle\rm \: N _{ \rm tile} =  \frac{A _{ \rm floor} }{A _{ \rm tile}  }

Thus substitute:

\displaystyle\rm \: N _{ \rm tile} =  \frac{360 \times 10000 {cm}^{2}  }{ {240cm}^{2}   }

simplify which yields:

\displaystyle\rm \: N _{ \rm tile} =  15000

hence,

15000 of tiles needed to tile the floor

9966 [12]3 years ago
4 0

Answer:

1500

Step-by-step explanation:

The area of the regtangular floor is 360m². The floor is going to be retired with tiles having area of 240cm² . We need to find the number of times . Therefore ,

\implies 360m^2 = 360 \times 10^4 \ cm^2

And , the number of tiles required will be ,

\implies n =\dfrac{Area \ of \ floor}{Area \ of \ a \ tile }\\\\\implies n =\dfrac{ 360 \times 10^4 \ cm^2}{240 cm^2} \\\\\implies \underline{\underline{ n = 1,500 }}

Hence the required answer is 1500 .

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Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

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Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

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1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

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Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0
3 years ago
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