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aniked [119]
3 years ago
5

Is a measure of 26 inches​ "far away" from a mean of 16 ​inches? As someone with knowledge of​ statistics, you answer​ "it depen

ds" and request the standard deviation of the underlying data. ​(a) Suppose the data come from a sample whose standard deviation is 2 inches. How many standard deviations is 26 inches from 16 ​inches? ​(b) Is 26 inches far away from a mean of 16 ​inches? ​(c) Suppose the standard deviation of the underlying data is 7 inches. Is 26 inches far away from a mean of 16 ​inches?
Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer: Hello!

In a normal distribution, between the mean and the mean plus the standar deviation, there is a 34.1% of the data set, between the mean plus the standar deviation, and the mean between two times the standard deviation, there is a 16.2% of the data set, and so on.

If our mean is 16 inches, and the measure is 26 inches, then the difference is 10 inches between them.

a) if the standar deviation is 2 inches, then you are 10/2 = 5 standar deviations from the mean.

b) yes, is really far away from the mean, in a normal distribution a displacement of 5 standar deviations has a very small probability.

c) Now the standar deviation is 7, so now 26 is in the range between 1 standar deviation and 2 standar deviations away from the mean.

Then this you have a 16% of the data, then in this case, 26 inches is not far away from the mean.

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PLEASE HELP! I’m struggling with each part any help will be amazing
Vlad [161]

Answer:

<u>slope:</u> -5/2

<u>y-intercept</u>: (0, 2)

<u>Linear function</u>: y = -5/2x + 2

Step-by-step explanation:

Given points (-2, 7) and (2, -3):

Use these points to solve for the slope of the line using the formula:

m = (y2 - y1)/(x2 - x1)

Let  (x1, y1) =  (-2, 7)

      (x2, y2) =  (2, -3)

Substitute these values into the equation:

m = (y2 - y1)/(x2 - x1)

m = (-3 - 7) / [2 - (-2)]

m = -10/ (2 + 2)

m = -10/4 = -5/2

Therefore, the  slope of the line in reduced form is m = -5/2.

The y-intercept is the <u>y-coordinate</u> of the point (0, <em>b</em>) where the graph of the linear equation crosses the y-axis of the Cartesian grid. The y-intercept is also the value of y when x = 0.

To solve for the y-intercept, use one of the given points (2, -3) and the slope (m = -5/2), and substitute their values into the slope-intercept form:

y = mx + b

-3 = -5/2(2) + b

-3 = -5 + b

Add 5 to both sides to solve for the y-intercept, b:

-3 + 5 = -5 + 5 + b

2 = b

Given the value of b = 2, it means that the y-intercept is (0, 2).

Therefore, given the slope of -5/2, and the y-intercept, b = 2:

The linear equation in slope-intercept form is: y = -5/2x + 2

Please mark my answers as the Brainliest, if you find this helpful :)

5 0
2 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
3 years ago
(9 x 10 ^10) - ( 4x10^10)
Marianna [84]

Answer:

5 * 10^10

Step-by-step explanation:

that's it bro. learn how to do it. then you won't need brainly anymore foo'.

4 0
3 years ago
Find the inverse of g(x)=1/3x - 7 and then find its domain and range if you can show steps that would be gladly appreciated than
Schach [20]

Answer:

g-1(x) = 3(x + 7).

Domain is All Real values of x.

Range is All Real values of the function.

Step-by-step explanation:

Let y = 1/3 x - 7

1/3 x = y + 7

Multiply both sides by 3:

x = 3(y + 7)

So the inverse of g(x) = g-1(x) = 3(x + 7).

Domain is All Real values of x.

Range is All Real values of the function.

6 0
3 years ago
See file attached below:
pochemuha

Answer:

Goodluck my dude.

Step-by-step explanation:

7 0
2 years ago
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