The equation of the perpendicular line is y + 7 = -1/7(x - 3)
<h3>How to determine the line equation?</h3>
The equation is given as
y = 7x + 14
Also, from the question
The point is given as
Point = (3, -7)
The equation of a line can be represented as
y = mx + c
Where
Slope = m
By comparing the equations, we have the following
m = 7
This means that the slope of y = 7x + 14 is 7
So, we have
m = 7
The slopes of perpendicular lines are opposite reciprocals
This means that the slope of the other line is -1/7
The equation of the perpendicular lines is then calculated as
y = m(x - x₁) +y₁
Where
m = -1/7
(x₁, y₁) = (3, -7)
So, we have
y = -1/7(x - 3) - 7
Evaluate
y = -1/7(x - 3) - 7
Add 7 to both sides
y + 7 = -1/7(x - 3)
Hence, the perpendicular line has an equation of y + 7 = -1/7(x - 3)
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The measure of angle ABC is 45°
<em><u>Explanation</u></em>
Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)
According to the diagram below....
Length of the side BC (a)
Length of the side AC (b)
Length of the side AB (c)
We need to find ∠ABC or ∠B . So using <u>Cosine rule</u>, we will get...
So, the measure of angle ABC is 45°
Answer:
B
Step-by-step explanation:
Because yes
Answer:
<em>angle ABD =</em><u><em>55 degree</em></u>
<em>angle BCD= </em><u><em>125 degree</em></u>
Step-by-step explanation:
angle ABD and angle DBC are supplementary angles.
Hence, angle ABD +angle DBC = 180 --equation 1
angle ABD = (2x+15) ---equation 2
angle BCD = (4x+45) ------equation 3
ABD+DBC=180
(2x+15) + ( 4x+45 ) = 180
2x+4x+15+45=180
6x+60=180
6x=180-60
6x=120
x=120/6=20
angle ABD= 2x+15= 2(20) +15
=40+15= 55 degree
angle BCD= 4x+45 = 4(20) +45
= 80+45= 125 degree
Hence, angle ABD =55 degree
angle BCD= 125 degree
<em>Hope this helps.</em>