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ValentinkaMS [17]
4 years ago
13

a crayon company recently changed its labels. it currently has 657,388 crayons with the old label and 82,923 crayons with the ne

w label. how many crayons does the company have in stock?
Mathematics
2 answers:
elena-14-01-66 [18.8K]4 years ago
3 0
It needs to be b or lest than that
AVprozaik [17]4 years ago
3 0

Answer:

740,311

Step-by-step explanation:

You add the two numbers, unless I'm missing something, college level?

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The length of a rectangle is 9 cm more then half the width. Find the length of the perimeter is 60cm
stira [4]

length = 1/2 w+9

perimeter= 60 =2(l+w)  

substitute in for length

60 = 2(1/2 w +9 +w)  

60 = 2 (3/2 w +9)

distribute

60 = 3w + 18

subtract 18 from each side

42 = 3w

divide by 3 on each side

14 = w

length = 1/2 w + 9

length = 1/2 (14) +9

              7 + 9

16cm

7 0
3 years ago
What is a correct way to evaluate the expression 80 - (50 – 35)?
Svetach [21]

Answer:

PEMDAS!!! (Parentheses, exponents, multiplication, division, addition, subtraction)

Step-by-step explanation:

Parentheses first!

50-35=15

Then subtraction!

80-15=65

Hope this helped!!! :)

6 0
3 years ago
Read 2 more answers
2 Points<br> What is the solution to this equation?<br> 4x + 16 - X= 22 + 6
Alinara [238K]

Answer:

x=12/5

Step-by-step explanation:

4x + 16 - x= 22 + 6

5x+16=28

5x=28-16

5x=12

x=12/5

8 0
3 years ago
In ABC, the sum of the measures of Angle A and angle B is 47°. What is the measure of Angle C ?
puteri [66]

Answer:

∠ C = 133°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , that is

∠ A + ∠ B + ∠ C = 180° ( substitute A + B = 47° )

47° + ∠ C = 180° ( subtract 47° from both sides )

∠ C = 133°

4 0
2 years ago
Read 2 more answers
Mr. Williams is building a sand box for his children. It costs $228 for the sand if he builds a rectangular-sand box with dimens
Andru [333]

Answer:  The correct option is (C) $342.

Step-by-step explanation:  Given that Mr. Williams is building a sand box for his children and is costs $228 for the sand if he builds a rectangular-sand box with dimensions 9 ft by 6 ft.

We are to find the cost of the sand if he decides to increase the size to 13\frac{1}{2}~\textup{ft by }9~\textup{ft}.

Since the box is empty from inside, so we will be considering the perimeter of the box, not area.

The perimeter of the rectangular-sand box with dimensions 9 ft by 6 ft is

P_1=2(9+6)=30~\textup{ft},

and the perimeter of the rectangular-sand box with dimensions 13\frac{1}{2}~\textup{ft by }9~\textup{ft}. is

P_2=2\left(13\dfrac{1}{2}\times9\right)=2(13.5\times9)=45~\textup{ft}.

Now, we will be using the UNITARY method.

Cost of sand for building rectangular-sand box with perimeter 30ft = $228.

So, cost of  sand for building rectangular-sand box with perimeter 1 ft will be

\$\dfrac{228}{30}.

Therefore, the cost of sand for building rectangular-sand box with perimeter 45 ft is given by

\$\dfrac{228}{30}\times45=\$342.

Thus, the required cost of the sand is $342.

Option (C) is CORRECT.

3 0
3 years ago
Read 2 more answers
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