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Vikentia [17]
3 years ago
8

Write the quadratic function in vertex form: f(x) = 8x2 + 2x - 5

Mathematics
2 answers:
const2013 [10]3 years ago
8 0

Answer:

y=8(x+\frac{1}{8} )^{2} -\frac{41}{8}

Step-by-step explanation:

The given quadratic function is

f(x)=8x^{2} +2x-5

Where a=8, b=2 and c=-5.

Now, let's find the vertex, which coordinates are V(h,k), and h=-\frac{b}{2a}

Replacing each value, we have

h=-\frac{2}{2(8)}=-\frac{1}{8}

Then, k=f(h), so

f(-\frac{1}{8} )=8(-\frac{1}{8} )^{2} +2(-\frac{1}{8} )-5=\frac{1}{8}-\frac{1}{4} -5=\frac{1-2-40}{8}\\  k=-\frac{41}{8}

So, the vertex is

V(-\frac{1}{8},-\frac{41}{8}) and a=8

Therefore, the vertex form is

y=a(x-h)^{2}+k\\ y=8(x+\frac{1}{8} )^{2} -\frac{41}{8}

Brilliant_brown [7]3 years ago
7 0
Hello : 
<span>f(x) = 8x² + 2x - 5
f(x) = 8(x²+1/4 x)-5
f(x) = 8(x²+2(1/8)x +(1/8)² -(1/8)² ) -5
f(x) = 8((x+1/8)²-1/8-5
f(x) = 8(x+1/8)²-41/5....(vertex form)</span>
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