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Zigmanuir [339]
3 years ago
10

Write an equation in slope - intercept form passing through (2,5); slope 3 over 4

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
We can use point slope form then convert to slope intercept

point slope
y-y1=m(x-x1)
m=slope
(x1,y1) is a givn point
point is (2,5)
slope is 3/4
y-5=3/4(x-2)
y-5=3/4x-6/2
add 5
y=3/4x-3+5
y=3/4x+2
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30 degrees

Step-by-step explanation:

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4 years ago
Raven is making pillows. Each pillow requires 3/5 yard of fabric. Raven has 6 yards of fabric. Use the number line to find 6 ÷ 3
katen-ka-za [31]

Answer:

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Step-by-step explanation:

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4 years ago
Can someone please explain?
AlladinOne [14]
<h2>Hello!</h2>

The answer is:

The correct option is the first option:  

y=-4x+64

<h2>Why?</h2>

To write the equation of the line in slope-interception  form we need to extract all the information that we need from the graphic.

We must remember that the slope-interception form of the lines is:

y=mx+b

Where,

y, is the function

m, is the slope of the line

x, is the variable

b, is the y-axis intercept

We can find the slope using the following formula:

m=\frac{ChangeInY}{ChangeInX}

Which is for this case:

m=\frac{64}{16}=4

As we can see from the graphic, the line is decresing, so the sign of the slope "m" will be negative, so:

m=-4

We can find the value of "b" seeing where the line intercepts the y-axis.

As we can see it intercept the y-axis at:  y=64

Then, now that we already know the value of "m" and "b", we can write the equation of the line:

y=mx+b=-4x+64\\y=-4x+64

So, the correct option is the first option:

y=-4x+64

Have a nice day!

4 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

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5 0
3 years ago
What is the missing angles
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