PEMDAS
2+3(2)^2/12
2+3(4)/12
2+12/12
2+1
Answer: 3
Let us set up some variables:
Now let us set up some equations based on the facts:
- length of rectangle is 4 times its width --> L = 4W
- perimeter of rectangle is 80 --> 2L + 2W = 80
Equations:
L = 4W -- equation 1
2L + 2W = 80 -- equation 2
Plug the value of L from equation 1 into equation 2
2(4W) + 2W = 80
8W + 2W = 80
10W = 80
W = 8 -- equation 3
Plug the value of W from equation 3 into equation 1:
L = 4W = 4 * 8 = 32
Therefore the length is 32 and the width is 8.
Hope that helps!
---------------------
<span>2+2(2+2*0)2+0
</span><span><span>2+2×(2+0)×2+0
</span><span><span>2+2×2×2+0
</span><span><span>2+8+0</span><span>
10
</span></span></span></span><span>---------------------
</span>
Answer
D
Hope this help you?
Answer:
I got y = 10
or
y = 24
or the answer is y = -5x since the 4 stays the same but the -5x changes
I feel like you have to replace with x with the numbers
Step-by-step explanation:
