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geniusboy [140]
3 years ago
6

Un objeto es lanzado verticalmente hacia arriba con una velocidad inicial v_o de 19,6m/s. La distancia d en metros del objeto de

spués de t segundos esta dada por la ecuación: d=v_0 t-4,9t^2
¿Cuánto tiempo debe pasar para que el objeto esté a 2 metros del suelo?
¿Cuándo el objeto alcanzará el suelo?
¿Cuándo el objeto estará a 12 metros del suelo?
¿Cuál es la altura máxima y cuando la alanzará?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

deverias pre guntar en matematicas pero no podre ayudarte

Step-by-step explanation:

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r-ruslan [8.4K]

Answer:

Add -4x to both sides--> 6x+9=4x-3 and 2x+9=-3

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3 years ago
Graph: y = 3x - 5<br> Plz help
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Answer:

The equation, y=3x-5 is in y=mx+b format. The b, or -5 in this case, tells you what the y intercept is, or in this case, your starting point. This means your first point will be at (0,-5). The mx, or 3x in this case, tell us how much to move     up and how much to move sideways. 3x is equal to 3/1x and the 3/1 tells us the rise/run. Rise being how much to go up or down and run being how much to go to the left or right. So in 3x, the rise is 3 and the run is 1. So you will go 3 up on the y axis and 1 to the right on the x-axis. So your next point will be (1, -2) and the point after that will be (2, 1) and so on!

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5 0
3 years ago
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What number produces an irrational number when added to 0.4
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4 years ago
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Answer:

The answer is 26

Step-by-step explanation:

24 + (3 × 5) - 4 - 9

= 24 + 15 - 4 - 9

= 39 - 13

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Thus, The answer is 26

<u>-TheUnknownScientist</u><u> 72</u>

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