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geniusboy [140]
3 years ago
6

Un objeto es lanzado verticalmente hacia arriba con una velocidad inicial v_o de 19,6m/s. La distancia d en metros del objeto de

spués de t segundos esta dada por la ecuación: d=v_0 t-4,9t^2
¿Cuánto tiempo debe pasar para que el objeto esté a 2 metros del suelo?
¿Cuándo el objeto alcanzará el suelo?
¿Cuándo el objeto estará a 12 metros del suelo?
¿Cuál es la altura máxima y cuando la alanzará?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

deverias pre guntar en matematicas pero no podre ayudarte

Step-by-step explanation:

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Solve the simultaneous equation x+y/4=1/2 and x-3y/3=2
Feliz [49]

Answer:

x+y/4 = 1/2

x-3y/3 = 2

move variables to one side:

multiply the first equation by 4 to get: x+y =2

and the second equation by 3 to get: x-3y =6

then subtract the equations to cancel out x:

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- x-3y = 6

then u get

y--3y = 2-6

4y = -4

y=-1

substitute to solve for x:

x-1 / 4 =1/2

x-1 = 2

x=3

check:

3+-1

2/4= 1/2

correct!!!

3 0
3 years ago
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If f (x)=3^5-x + 6, what is the value of f (5), to the nearest tenth?
Amiraneli [1.4K]

Answer:

240

Step-by-step explanation:

3^5 - 5 + 6

243 - 5 = 238+6= 244

240?

8 0
3 years ago
Please help i dont understand
Rama09 [41]

Answer:

17.5

Step-by-step explanation:

Pythagorean Theorem is a^2 + b^2 =c^2

a= 9 , b= 15, c= x

9^2 + 15^2 = c^2

\sqrt{306}= c^2

c= 17.493 or 17.5 rounded to the nearest tenth

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3 years ago
Nd the 52nd term and the term named in the problem <br>40, 140, 240, 340, ...<br>Find a 32​
Galina-37 [17]

Answer:

5140 and 3140

Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

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This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 40 and d = 100, thus

a_{52} = 40 + (51 × 100) = 40 + 5100 = 5140

a_{32} = 40 + (31 × 100) = 40 + 3100 = 3140

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Answer:

sin25 = cos65

Step-by-step explanation:

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3 years ago
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