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geniusboy [140]
3 years ago
6

Un objeto es lanzado verticalmente hacia arriba con una velocidad inicial v_o de 19,6m/s. La distancia d en metros del objeto de

spués de t segundos esta dada por la ecuación: d=v_0 t-4,9t^2
¿Cuánto tiempo debe pasar para que el objeto esté a 2 metros del suelo?
¿Cuándo el objeto alcanzará el suelo?
¿Cuándo el objeto estará a 12 metros del suelo?
¿Cuál es la altura máxima y cuando la alanzará?
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

deverias pre guntar en matematicas pero no podre ayudarte

Step-by-step explanation:

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Answer is 12.50. u can comment on my answer if you would like to see how that is the correct answer :)
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I dO nOt coMprEheNd PLEASE HELPPP
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Lines y=-x+2 and y=3x+1 intersect the y=axis. If you plot them out on a graph using the equation y=mx+b, then they are parallel and are set on the y-axis.
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A video game was originally priced at $60.
pantera1 [17]

Answer: 71

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3 years ago
A boiler room has the shape of a rectangular prism. The area of the floor of the room is 112 square feet. The length of the room
Naddik [55]

Answer:

Length = 16 feet.

Width = 7 feet

Height = 8 feet

Volume = 896 cubic feet.

Step-by-step explanation:

There is a rectangular prism boiler room. 112 square feet is the floor area of the room.

Let the length of the room is L feet and width is W feet.

So, LW = 112 ...... (1)

Now, given that L = 2 + 2W ........ (2) , hence, from equation (1) we get  

(2 + 2W)W = 112

⇒ 2w + 2w² = 112

⇒ W² + W - 56 = 0

⇒ (W +8)(W - 7) = 0

⇒ W = 7 feet. {Neglecting the negative root as W can not be negative}

Hence, from equation (2) we get L = 2W + 2 = 16 feet.

Now, 1 foot more than the width is the height H.

Hence, H = 7 + 1 = 8 feet.

Therefore, the volume of the room is, V = LWH = 16 × 7 × 8 = 896 cubic feet. (Answer)

5 0
3 years ago
A right rectangular prism is 5 1/4 in. wide, 12 1 2 in. long, and 4 in. tall.
lozanna [386]

Answer: V = 262\frac{1}{2} cm^{3}

Step-by-step explanation:

V = LWH

V = 5\frac{1}{4} X 12\frac{1}{2} X 4

V = \frac{21}{4} X \frac{25}{2} X \frac{4}{1}

V = \frac{525}{2}

V = 262\frac{1}{2} cm^{3}

7 0
3 years ago
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