Un objeto es lanzado verticalmente hacia arriba con una velocidad inicial v_o de 19,6m/s. La distancia d en metros del objeto de
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Answer:
t = 0.293 s and 14.52 s
Step-by-step explanation:
The heights of the ball in feet is given by the equation as follows :
Where t is the number of seconds after the ball was thrown.
We need to find is the ball 18 ft above the moon's surface.
Put S = 18 ft
It is a quadratic equation. Its solution is given by :
So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.