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kompoz [17]
3 years ago
9

Solve for the variable in each equation.

Mathematics
1 answer:
vaieri [72.5K]3 years ago
5 0
All of the answers are 0
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Write a coordinate proof for the following statement: Any triangle ABC formed so that vertex C is on the perpendicular bisector
AnnyKZ [126]

Answer:

Answer is contained in explanation.

Step-by-step explanation:

Description of visual:

I started with the first picture. This is a picture of triangle ABC.

Now I'm going to draw a line segment from vertex C such that it is  a perpendicular bisector of AB.

Proof:

CM is a perpendicular bisectors of AB is a given.

From this we can concluded by definition of perpendicular angles that angle AMC and angle BMC are right angles.

Since angles AMC and BMC are right angles, then they are congruent to each other.

By the definition of bisector and since CM bisects AB, then AM is congruent to MB.

By the reflexive property, we have that CM is congruent to CM.

We can conclude the two triangles, triangle CMA and CMB, are congruent by SAS Postulate.

Since triangles CMA and CMB are congruent, we can conclude that their corresponding parts are congruent.

Since their corresponding parts are congruent, then we now know that side CA and side CB are congruent.

Since two sides of the triangle ABC are congruent to each other, namely side CA and side CB, then the triangle ABC is an isosceles triangle.

//

Setup for coordinate geometry proof:

M is the midpoint of AB since CM is a bisector of AB.

Since M is the midpoint of AB, then M is located at the coordinates (\frac{0+b}{2},\frac{0+0}{2})=(\frac{b}{2},0).

We found this point such that the length AM is equal to the length MB.

That is, the distance between A and M is the same as the distance between M and B.

Let's check.

AM=\sqrt{(\frac{b}{2}-0)^2+(0-0)^2}

AM=\sqrt{(\frac{b}{2})^2+0}

AM=\sqrt{\frac{b^2}{4}}

AM=\frac{\sqrt{b^2}}{\sqrt{4}}

AM=\frac{b}{2}

MB=\sqrt{(b-\frac{b}{2})^2+(0-0)^2}

MB=\sqrt{(\frac{b}{2})^2+0}

MB=\sqrt{\frac{b^2}{4}}

MB=\frac{\sqrt{b^2}}{\sqrt{4}}

MB=\frac{b}{2}

We have confirmed that AM=MB.

(Based on the picture, we could have taken a slightly easier route to calculate the distance between M and A, then the distance between B and M. They are both a horizontal distance. So MB=b-\frac{b}{2}=\frac{b}{2} where as AM=\frac{b}{2}-0=\frac{b}{2}.)

Now we also want to assume that the line segment CM is perpendicular to AB. I have drawn the base of the triangle on the x-axis so a vertical line would be perpendicular to it. Also this would make point C=(c,d)=(\frac{b}{2},d). The y-coordinate is d because we don't know how high above the x-axis the point C is.

If we show CA=CB, then we have shown triangle ABC is an isosceles.

Coordinate Geometry Proof:

We want to finally show that the sides CB and CA of triangle ABC are congruent. We will do this using distance formula.

That is we want to show the distance between (b/2,d) and (0,0) is the same as (b/2,d) and (b,0).

CB=\sqrt{(b-\frac{b}{2})^2+(0-d)^2}

CB=\sqrt{(\frac{b}{2})^2+(-d)^2}

CB=\sqrt{\frac{b^2}{4}+d^2}

CA=\sqrt{(\frac{b}{2}-0)^2+(d-0)^2}

CA=\sqrt{(\frac{b}{2})^2+d^2

CA=\sqrt{\frac{b^2}{4}+d^2

Thus, CA=CB. Since CA=CB, then the triangle is an isosceles.

//

3 0
4 years ago
You have a job filling cylinder-shaped tubes with flavored sugar. Your boss asks you to find the volume of a tube that is 21 inc
borishaifa [10]
To find the approximately volume you will use the formula for finding the volume of a cylinder:

V = pi x r^2 x h
      3.14 x 0.5^2 x 21
V = 16.485

The volume is approximately 16.49 cubic inches.
5 0
3 years ago
Read 2 more answers
Marcos has 3/5 of a pizza remaining and gives his friend 1/5 of the remaining pizza. How much pizza is left over?
LuckyWell [14K]

Answer

at first I said 1/2 but it's 2/5's.

Step-by-step explanation:

\frac{3}{5}  -  \frac{1}{5 }  =  \frac{2}{5}

3 0
4 years ago
PLEASE HELPPPPP!!! GIVING BRAINLIEST!!!!
lina2011 [118]

The integers that make the linear equation false are:

3, 78, and 126

We found that by evaluating the equation in all the options.

<h3>Which integers make the equation false?</h3>

Here we have the linear equation:

8m - 15 = 5m + 63

And the possible solutions are:

S: {3, 26, 78, 126}

To see which of these integers make the equation false, we can replace the value of m by the given values and see when the equation is false (the number in the left is different to the one in the right).

if m = 3

8*3 - 15 = 5*3 + 63

9 = 78    this is false.

if m = 26

8*26 - 15 = 5*26 + 63

193 = 193  this is true.

if m = 78

8*78 - 15 = 5*78 + 63

609 = 453  this is false.

if m= 126

8*126 - 15  = 5*126 + 63

993 = 693  this is false.

So the integers that make the equation false are:

3, 78, and 126.

Learn more about linear equations:

brainly.com/question/1884491

#SPJ1

5 0
1 year ago
PLEASE HELP DUE IN 20 MINS!!!! SOLVE ALL 4
Bogdan [553]

1. I Have no clue

2. -2

3. I have no clue

4. 77

8 0
3 years ago
Read 2 more answers
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