Answer:
The cell interior would experience higher than normal Na+ concentrations and lower than normal K+ concentrations.
Explanation:
Na+/K+ ATPase exists in two forms: Its phosphorylated form has a high affinity for K+ and low affinity for Na+. ATP hydrolysis and phosphorylation of the Na+/K+ pump favor the release of Na+ outside the cell and binding of K+ ions from the outside of the cell. Dephosphorylation of the pump increases its affinity for Na+ and reduces that for K+ ions resulting in the release of K+ ions inside the cells and binding to the Na+ from the cells.
The presence of ATP analog would not allow the pump to obtain its phosphorylated form. Therefore, Na+ ions would not be released outside the cells. This would increase the Na+ concentration inside the cell above the normal. Similarly, the pump would not be able to pick the K+ from the outside of the cell resulting in reduced cellular K+ concentration below the normal range.
Answer:
Explanation:
Sister chromatids are regarded as replicated chromosomes. Sister chromatids are two identical copies of chromosomes held at the centromere that are formed as a result of replication. They are identical in the sense that they contain same alleles/gene sequence of the same genes.
Homologous chromosomes, on the other hand, are similar (in length, centromere position) but non-identical chromosomes. Homologous are non-identical in the sense that they may contain different alleles of a gene and are received from each parent. homologous chromosome contain four chromatids; two of which are sister chromatids and non-sister to the other two.
Both undergo meiosis where homologous chromosomes separate in meiosis I while sister chromatids separate in meiosis II but only sister chromatids undergo mitosis.
We need the options in order to answer
The regression equation is:
y = 1.15 – 0.251 x₁ + 0.078 x₂ + 0.306 x₁x₂
<span>
<span>
<span>
Where,
x₁ = -0.2508
x₂ = 0.0777
x₁x₂ = 0.3058
Inserting the values,
<span>
<span>
</span></span>y = 1.15 – {0.251 × (-0.2508)} + {0.078 ×(0.0777)} + {0.306 × (0.3058)}
</span></span></span>
y = 1.15 - (- 0.0629508) + 0.0060606 + 0.935748
y = 1.15 + 0.0629508 + 0.0060606 + 0.935748
y = 1.3125862
Answer:
x₁ and x₂ are main effects (a type of tuna and type of packing liquid) that contribute significant information for the prediction of <span>y.</span>
