Answer:
Value of given expression x is -4
Step-by-step explanation:
Given equation in question;
4 + 2|3x + 4| = -4
Find:
Value of given expression
Computation:
4 + 2|3x + 4| = -4
Using BODMAS rule;
⇒ 4 + 2|3x + 4| = -4
⇒ 2|3x + 4| = - 4 - 4
⇒ 2|3x + 4| = - 8
⇒ |3x + 4| = - 8 / 2
⇒ |3x + 4| = - 4
⇒ 3x + 4 = - 8
⇒ 3x = -8 - 4
⇒ 3x = -12
⇒ x = -12 / 3
⇒ x = -4
Value of given expression x is -4
Answer: The length is 510 and the width is 110.
Step-by-step explanation:
To find the area of a rectangle, you will have to add the 2 times the length plus 2 times the width because a rectangle have 4 sides. Two widths and two lengths.
You can now use the formula P= 2l + 2w
were P is the perimeter , l is the length, and w is the width.
the length is 400 more than the width, so we can represent that by the equation, l = w + 400
And now we know that the width is w.
So now we will input the perimeter, length, and into the formula to solve for w.
1240 = 2(w + 400) + 2w
1240 = 2w + 800 + 2w
1240 = 4w + 800
-800 -800
440 = 4w
w = 110
L= 110 + 400
L = 510
Check :
1240 = 2(510) + 2(110)
1240 = 1020 + 220
1240 = 1240
I had the same question on my hw and I picked c \(“-)/
Answer:
The answer is the graph D
Step-by-step explanation:
The inequation states that:
abs(x) >3.
By definition, the absolute value | x | is the distance of x from zero. In this case: | x | > 3 The solution is going to be all the points that are greater than three units away from zero.
For that reason the solution is -3>x>3. That is to say, all values greater than 3 or less than -3 are solutions.
Answer:
Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]
Step-by-step explanation:
We are given that a function
Interval [1,5]
The given function is defined on this interval.
Hypothesis of Mean Value Theorem:
(1) Function is continuous on interval [a,b]
(2)Function is defined on interval (a,b)
From the graph we can see that
The function is continuous on [1,5] and differentiable at(1,5).
Hence, the function satisfies the hypothesis of the Mean Value Theorem.
