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blagie [28]
4 years ago
15

What is 63 as the product of prime factors in ascending order?

Mathematics
1 answer:
just olya [345]4 years ago
6 0
When we arrange the numbers in such an order that it starts from the smallest number and goes towards the largest number, that order is called ascending order.
Prime factors of 63 are : 3, 3, 7
As 3 repeats and 3 is smaller than 7 so, when we write this in ascending order as the product of these, we write in such a way;
63 = 3 x 3 x 7 = 3² x 7
Now 3² = 9 and 9 is greater than 7,so,
63 = 7 x 9
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3 years ago
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shusha [124]

Answer:

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Step-by-step explanation:

We have the algebraic expression and are asked to solve for x.

To solve, we need to isolate x.

2x + 22 = 4(x + 3)

Distribute :

2x + 22 = (4(x) + 4(3))

2x + 22 = 4x + 12

Subtract 12 from both sides :

2x + 10 = 4x

4x = 2x + 10

Subtract 2x from both sides :

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5 0
3 years ago
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11x + 12 = 8x - 9 ... please
Marat540 [252]

Assignment: \bold{\Solve \ Equation: \ 11x+12=8x-9}

<><><><><><><>

Answer: \boxed{\bold{x=-7}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Subtract 12 From Both Sides

\bold{11x+12-12=8x-9-12}

[ Step Two ] Simplify

\bold{11x=8x-21}

[ Step Three ] Subtract 8x From Both Sides

\bold{11x-8x=8x-21-8x}

[ Step Four ] Simplify

\bold{3x=-21}

[ Step Five ] Divide Both Sides By 3

\bold{\frac{3x}{3}=\frac{-21}{3}}

[ Step Six ] Simplify

\bold{x=-7}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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