Ask question

Ask question

All categories

3 years ago

12

2/x = 10/15 it's 2 / x = 10 / 15 find the unknown number in the proportion. Round the answer to the nearest hundredth when neces

sary Will mark brainly

2 answers:

Ratling [72]3 years ago

6 0

Answer:

x = 3

Step-by-step explanation:

2/x = 10/15

10x = 30

x = 3

Masteriza [31]3 years ago

3 0

Answer:

3

Step-by-step explanation:

You might be interested in

In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d

muminat

It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76°

3 0

3 years ago

Hey guy pls help <br> explain answer <br> no links

laiz [17]

Answer:

4, 5

Step-by-step explanation:

the mode is 4 since mode is the number/s that appear most. Median is the number in the middle when the range is in order. That is 5

8 0

3 years ago

what is the type of conic section is given by the equation x^2-9y^2=900 an waht is the domain and range?

Talja [164]

When the squared terms are of different signs, the equation generally describes a hyperbola. This one has its vertices at x=±30, so the parameters of interest are
domain: (-∞, -30] ∪ [30, ∞)
range: (-∞, ∞)

8 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

Read 2 more answers

Drag each equation to show if it could be a correct first step to solving the equation 2(x+7)=36

sdas [7]

2(x + 7) = 36 |use distributive property

(2⋅x)+(2⋅7)=36

2·x+2·7=36

2x + 14 = 36

2(x + 7) = 36 |:2

x + 7 = 18

Answer (bold expressions).

7 0

3 years ago

Read 2 more answers