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Nata [24]
2 years ago
11

A gift basket has 2 soaps and 5 lotions and costs $20. A second basket has 6 spas and 15 lotions and cost $60. Is it possible to

determine the price of the soap?
Mathematics
1 answer:
kifflom [539]2 years ago
3 0

A second basket has 6 spas--- I think you mean 6 soaps , so i will work with that

Answer:it is not possible to determine the price of the soap with the information given.

Step-by-step explanation:

Let s0ap be represented as x

and lotion be represented as y

2 soaps and 5 lotions costing  $20 gives us equation 1 as

2 x+ 5y= 20-------- equation 1

second basket with 6 soaps and 15 lotions and costing $60 gives us equation 2 as

6x + 15y= 60------equation 2

Step 2 -- Solving

2 x+ 5y= 20-------- equation 1

6x + 15y= 60--------equation 2

BY elimination method, we  multiply equation 1 by (3)

2x + 5y= 20  x (3)

6x + 15y=60-------equation 3

Subtraction of equation 3 from equation 2 gives us

6x + 15y=60-------equation 3

-6x + 15y= 60--------equation 2

0x +0y=0  which is no solution

Therefore it is not possible to determine the price of the soap

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Using number line what is 4-5​
Vinil7 [7]

Answer:

<h2>-1</h2>

Step-by-step explanation:

4 - 5 = -1

Count:

4, 3, 2, 1, 0, <u>-1</u>

6 0
2 years ago
Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided
DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0
2 years ago
The sum of two integers is 33. The larger is 6 more than twice the smaller. Find the two
grandymaker [24]

Answer:

24 and 9

Step-by-step explanation:

Hi there!

Let x be equal to the larger integer.

Let y be equal to the smaller integer.

<u>1) Construct equations</u>

  1. x+y=33 (The sum of two integers is 33)
  2. x=6+2y (The larger is 6 more than twice the smaller)

<u>2) Solve for one of the integer</u>

Isolate x in the first equation

x+y=33\\x=33-y

Plug the first equation into the second

33-y=6+2y

Combine like terms

33-6=2y+y\\27=3y\\9=y

Therefore, the smaller integer is 9.

<u />

<u>3) Solve for the other integer</u>

x+y=33

Plug in y (9)

x+9=33\\x=33-9\\x=24

Therefore, the larger integer is 24.

I hope this helps!

4 0
3 years ago
Read 2 more answers
Evaluate 3x +2y - 4z/x for x =5, y=-2,z=10
Evgen [1.6K]

3x + 2y - 4z/x for x=5, y=-2, z=10

3x + 2y - 4z/x

3(5) + 2(-2) - 4(10)/(5)

15 - 4 - 40/5

15 - 4 - 8

11 - 8

3

3 0
2 years ago
Hill can make 2/5 a dozen cookies in 1/3 hour, what is his rate per hour
Setler [38]

Answer:1 1/5 dozen cookies a hour

Step-by-step explanation: hope it helps

3 0
2 years ago
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