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ryzh [129]
3 years ago
9

Please help.........

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0

the answer is....

False

Lilit [14]3 years ago
7 0

Answer:

False

Step-by-step explanation:

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Percents can be expressed as fractions and decimals. A percent means “out of 100,” so we can express 40% as the fraction 40⁄100.
stiks02 [169]

Answer:

Definitely 3/4!

Step-by-step explanation:

Option A = 7.5

Option B = 66.6%

Option C = 75% (because 25 times 4 is equal to 100%, so 25 times 3 would be 75)

Option D = 6/10 or 60%

5 0
3 years ago
What is the equation of the circle in standard form see attachment
Elodia [21]

Center (-1,1), radius 5 so

(x - -1)^2 + (y - 1)^2 = 5^2

(x+1)^2 + (y-1)^2 = 25

Third choice

7 0
4 years ago
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Please help me! I’ll mark as brilliant
IrinaVladis [17]

Answer: 30 i believe

Step-by-step explanation:

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3 years ago
Solve for x. Round to the nearest tenth if necessary.
Natasha2012 [34]

Answer:

x = 16

Step-by-step explanation:

9/12 = 12/x

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7 0
3 years ago
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Independent random samples taken on two university campuses revealed the following information concerning the average amount of
love history [14]

Answer:

p_v =P(t_{88}>6.960) =2.91x10^{-10}

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group A is significantly lower than the mean for the group B.  

Step-by-step explanation:

The statistic to test the hypothesis is given by this formula:

t=\frac{(\bar X_A-\bar X_B)-(\mu_{A}-\mu_B)}{\sqrt{\frac{s_A^2}{n_A}}+\frac{s_B^2}{n_B}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom

The system of hypothesis on this case are:

Null hypothesis: \mu_A \leq \mu_B

Alternative hypothesis: \mu_A >\mu_B

Or equivalently:

Null hypothesis: \mu_A - \mu_B \leq 0

Alternative hypothesis: \mu_A -\mu_B>0

Our notation on this case :

n_A =50 represent the sample size for group A

n_B =40 represent the sample size for group B

\bar X_A =280 represent the sample mean for the group A

\bar X_B =250 represent the sample mean for the group B

s_A=20 represent the sample standard deviation for group A

s_B=23 represent the sample standard deviation for group B

And now we can calculate the statistic:

t=\frac{(280 -250)-(0)}{\sqrt{\frac{20^2}{50}}+\frac{23^2}{40}}=6.511

Now we can calculate the degrees of freedom given by:

df=50+40-2=88

And now we can calculate the p value using the alternative hypothesis:

p_v =P(t_{88}>6.960) =2.91x10^{-10}

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group A is significantly lower than the mean for the group B.  

8 0
3 years ago
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