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Mumz [18]
2 years ago
9

I GIVES BRAINLIEST IF U SOLVE IT

Mathematics
1 answer:
kkurt [141]2 years ago
5 0

Answer:

False

Step-by-step explanation:

The following statement is false so in conclusion it will not be enough for both bird houses

Cleopatra= 12 1/2

Jesse=6-10

20ft will not be enough for both jesse and cleopatra !

Hope this helps

                                                                                            -<em>Tobie The dog <3</em>

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If y varies directly with x, and y=-1 when x=3
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where da question at

Step-by-step explanation:

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2(3x+2)=6x+4 linear equations
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Answer:

0 or 6x+4=6x+4  (Technically no slope at all!!)

Step-by-step explanation:

You need to do distributive property and then solve for x!!

meaning the 2(3x+2) has to get distributive property process.

6x+4=6x+4

That shall be equal together!!! (You could stop here!!)


If continue:

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2 years ago
Round 11,234 in 4 different ways
mafiozo [28]
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3 years ago
Richard's bakery sold 7 triple-chocolate birthday cakes in six weeks for 60 dollars each. The price of each cake was five times
Soloha48 [4]
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2 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
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