Making the usual substitutions (x=r·cos(θ), y=r·sin(θ)), you have
(r·cos(θ))² +4r·cos(θ) +4 + (r·sin(θ))² -4r·sin(θ) +4 = 8
r(r +4·cos(θ) -4·sin(θ)) = 0
Dividing by r then subtracting the non-r terms gives
r = 4(sin(θ) -cos(θ))
Answer:
1. 2x=5
Divide both by 2, x=2.5
2. y+1.8=14.7
Subtract 1.8 from both sides to isolate the variable, x=12.9
3. 6=1/2z
Multiply each side by 2 to isolate the variable, 12=z
4. 3 1/4 = 1/2+w
Isolate the variable by subtracting 1/2 to both sides, 2 3/4 = w
5. 2.5t=10
Divide each side by 2.5 to isolate the variable, t=4
Step-by-step explanation:
Answer:
She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6
Step-by-step explanation:
It looks like she didn't fully distribute the -
(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original
x3+ 2x2 - x + x3 – 2x2 +6 :Changed
~
(x3 + 2x2 - x)-(-x3 + 2x2 + 6)
x3 + 2x2 - x + x3 - 2x2 - 6
x3 + x3 + 2x2 - 2x2 -x - 6
2x3-x-6
I hope this helps ^-^
Answer:
x = -12
Step-by-step explanation:
Step 1: Subtract 2x from both sides
2x + 10 = -14
Step 2: Subtract 10 from both sides
2x = -24
Step 3: Divide both sides by 2
x = -12
2.48 / 0.4
Multiply both top and bottom by 10
(2.48 * 10) / (0.4 * 10)
24.8 / 4
6.2
Hope this explains it.
