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gavmur [86]
3 years ago
13

I-i need help, please️️

Biology
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

A single ruler

Explanation:

autocracies contain people with absolute power who doesn't need anyone else's approval to make laws.

an absolute monarchy contains a king or queen

so overall both contain 1 ruler :)

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Which of the following is FALSE about ribose and nucleotide and
Alex_Xolod [135]

Answer:

The correct answer is option c) "It is necessary to have a completely functioning pentose phosphate pathway for a tissue to synthesize ribose phosphates".

Explanation:

While the pentose phosphate pathway is the most common way at which a tissue synthesize ribose phosphate, it is false to affirm that it is necessary for ribose phosphate synthesis. Tissues have alternatives to the pentose phosphate pathway to synthesize ribose phosphate. For instance, the nucleotide salvage or the salvage pathway allows tissues to synthesize ribose phosphate from intermediates in the degradative pathway for nucleotides.

6 0
3 years ago
Does skim milk contain roughage?​
egoroff_w [7]

Answer:

Yes.

Explanation:

6 0
3 years ago
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When vesicles of the cardiac sarcoplasmic reticulum (CSR) are incubated with ATP Mg^2+ and Ca^2+, they take up Ca^2+ and reach a
abruzzese [7]

Answer

I added 4 and 5 as an attachment due to time constraint.

Explanation:

1. at a steady state ca2+ taken by vesicle = 40n/mol

enclosed volume of CSR = 5μ/mg

concentration of ca2+ in vesicle =

40*10⁻⁶/5x10⁻⁶

= 0.008

= 8x10⁻⁹mol/L

2. radius of circle =75nM

volume = 150nm

volume of vesicle = 4/3 x pi x r³

= 1.33 x 3.14 x (75x10⁻⁹)³

= 1.77 x 10⁻²¹

when we convert this we get

1.77x10⁻¹⁸L since 1m³ is equal to 100oL

surface area =4x3.14x(75x10⁻⁹)²

= 12.56x5.625⁻¹⁵

= 7.065x10⁻¹⁴m²

this is 7.065x10⁻¹⁰cm²

3. number of vesicle/CSR

= 5x10⁻⁶/1.77x10⁻¹⁸

= 2.824x10¹²

surface are = 2.824x10¹² x7.06x10⁻¹⁰

= 19.95x10²

8 0
3 years ago
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4 0
4 years ago
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sergejj [24]
We suppose the black fur is A and the white fur is a. The capital letter represents the dominant. Then the heterozygous black male is Aa and homozygous white female is aa. Then the offspring has two types, Aa and aa. The possibility of these two is equal and both are 50%.
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