The given radius is = 60 feet
The volume of the sphere is given by = ![\frac{4}{3} \pi r^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E%7B3%7D)
So we will find the volume of the sphere using radius as 60 and pi as 3.14
Volume =
= 902059.20 cubic feet
As quarter of anything is defined as its one-fourth part, so here the volume of the quarter of sphere can be calculated by finding one fourth of the calculated volume.
So volume of quarter sphere = ![\frac{902059.20}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B902059.20%7D%7B4%7D)
= 225514.80 cubic feet
And rounding this to nearest whole number we get 225515 cubic feet as the answer.
3m^2+2p^2-15
3(3)^2+2(10)^2-15
3(9)+2(100)-15
21+200-15
206
Answer:
<h2>which question dear..maybe you forgot to add the attachment...</h2>
Do you have A picture of the line?
Distance Formula: ![D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2)
Apply the points: ![D=\sqrt{(8-(-6))^2+((-2)-5)^2](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%288-%28-6%29%29%5E2%2B%28%28-2%29-5%29%5E2)
Solve: ![D=\sqrt{(8-(-6))^2+((-2)-5)^2}\\D=\sqrt{14^2+(-7)^2}\\D=\sqrt{169+49}\\D=\sqrt{218}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B%288-%28-6%29%29%5E2%2B%28%28-2%29-5%29%5E2%7D%5C%5CD%3D%5Csqrt%7B14%5E2%2B%28-7%29%5E2%7D%5C%5CD%3D%5Csqrt%7B169%2B49%7D%5C%5CD%3D%5Csqrt%7B218%7D)
Since the square root of 218 cannot be simplified, the answer is
![D=\sqrt{218}](https://tex.z-dn.net/?f=D%3D%5Csqrt%7B218%7D)
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